Patent Application
20110013777
The present invention relates generally to compression/decompression of data. More particularly, the invention relates to multiple keys for decoding, including creating the keys during data encoding. Techniques for storing multiple keys and file forms are also disclosed as are keys during instances of encoding with “fast approximation.”
Recent data suggests that nearly eighty-five percent of all data is found in computing files and growing annually at around sixty percent. One reason for the growth is that regulatory compliance acts, Statutes, etc., (e.g., Sarbanes-Oxley, HIPAA, PCI) force companies to keep file data in an accessible state for extended periods of time. However, block level operations in computers are too lowly to apply any meaningful interpretation of this stored data beyond taking snapshots and block de-duplication. While other business intelligence products have been introduced to provide capabilities greater than block-level operations, they have been generally limited to structured database analysis. They are much less meaningful when acting upon data stored in unstructured environments.
Unfortunately, entities the world over have paid enormous sums of money to create and store their data, but cannot find much of it later in instances where it is haphazardly arranged or arranged less than intuitively. Not only would locating this information bring back value, but being able to observe patterns in it might also prove valuable despites its usefulness being presently unknown. However, entities cannot expend so much time and effort in finding this data that it outweighs its usefulness. Notwithstanding this, there are still other scenarios, such as government compliance, litigation, audits, etc., that dictate certain data/information be found and produced, regardless of its cost in time, money and effort. Thus, a clear need is identified in the art to better find, organize and identify digital data, especially data left in unstructured states.
In search engine technology, large amounts of unrelated and unstructured digital data can be quickly gathered. However, most engines do little to organize the data other than give a hierarchical presentation. Also, when the engine finds duplicate versions of data, it offers few to no options on eliminating the replication or migrating/relocating redundancies. Thus, a further need in the art exists to overcome the drawbacks of search engines.
When it comes to large amounts of data, whether structured or not, compression techniques have been devised to preserve storage capacity, reduce bandwidth during transmission, etc. With modern compression algorithms, however, they simply exist to scrunch large blocks of data into smaller blocks according to their advertised compression ratios. As is known, some do it without data loss (lossless) while others do it “lossy.” None do it, unfortunately, with a view toward recognizing similarities in the data itself.
From biology, it is known that highly similar species have highly similar DNA strings. In the computing context, consider two word processing files relating to stored baseball statistics. In a first file, words might appear for a baseball batter, such as “batting average,” “on base percentage,” and “slugging percentage,” while a second file might have words for a baseball pitcher, such as “strikeouts,” “walks,” and “earned runs.” Conversely, a third file wholly unrelated to baseball, statistics or sports, may have words such as “environmental protection,” “furniture.” or whatever comes to mind. It would be exceptionally useful if, during times of compression, or upon later manipulation by an algorithm if “mapping” could recognize the similarity in subject matter in the first two files, although not exact to one another, and provide options to a user. Appreciating that the “words” in the example files are represented in the computing context as binary bits (1's or 0's), which occurs by converting the English alphabet into a series of 1's and 0's through application of ASCII encoding techniques, it would be further useful if the compression algorithm could first recognize the similarity in subject matter of the first two files at the level of raw bit data. The reason for this is that not all files have words and instead might represent pictures (e.g., .jpeg) or spread sheets of numbers.
Appreciating that certain products already exist in the above-identified market space, clarity on the need in the art is as follows. One, present day “keyword matching” is limited to select set of words that have been pulled from a document into an index for matching to the same exact words elsewhere. Two, “Grep” is a modern day technique that searches one or more input files for lines containing an identical match to a specified pattern. Three. “Beyond Compare,” and similar algorithms, are line-by-line comparisons of multiple documents that highlight differences between them. Four, block level data de-duplication has no application in compliance contexts, data relocation, or business intelligence.
The need in the art, on the other hand, needs to serve advanced notions of identifying new business intelligence, conducting operations on completely unstructured or haphazard data, and organizing it, providing new useful options to users, providing new user views, providing new encryption products, and identifying highly similar data, to name a few. As a byproduct, solving this need will create new opportunities in minimizing transmission bandwidth and storage capacity, among other things. Naturally, any improvements along such lines should contemplate good engineering practices, such as stability, ease of implementation, unobtrusiveness, etc.
Regarding the use of keys to encrypt and decrypt information, it is known to have “dual control” to guard access to important assets. For example, the concept of a two-key safe deposit box at a local banking institution is well understood. The bank retains one key, and the customer retains the other. To access the contents held in the box, both keys must be present and utilized. Not only does this protect the bank against allegations of improper access, it protects the box renter since a stolen key does not allow unilateral access. As another example, “dual control” typifies the two-person rule for handling launch codes for a nuclear missile. Only when two parties bring the correct keys to the lockbox can the box be opened and the codes revealed.
Regarding the keys themselves, encryption and decryption procedures require the use of secret information, e.g., the “key.” Common methods of controlling access to information in data security include single secret key encryption, sequential double encryption, and public key encryption. These methods provide less secure means of access control than can be realized using the two-key method to be described in this document.
In a symmetric encryption with a single secret key, the same key is used for both encryption and decryption. Single key encryption methods provide data security, but do not provide the advantages of “dual control.”
Sequential double encryption methods use two keys, but they do not require “dual control” because its keys are not used simultaneously. Furthermore, sequential double encryption requires that the order in which the keys are applied be known and preserved. The two-key decryption method described herein requires that both keys be simultaneously available at decryption time. There is no sequential use, so there is no ordering issue.
In a public-key encryption method, also referred to as asymmetric encryption, each user has both a public key and a private key. Applying an algorithm to a random number generates the two keys for each user. Encryption is performed with the public key, and decryption is done with a private key. A third party can certify the ownership of key pairs. The users' private keys are kept secret, while their public keys might be distributed widely. The two-key embodiment discussed below does not lend itself to public key and private key scenarios because both of its keys are used simultaneously to decrypt the data.
Accordingly, a further need in the art is identified to overcome the problems of traditional keys and their usage.
The foregoing and other problems become solved by applying the principles and teachings associated with the encryption/decryption of digital data using related, but independent keys. Broadly, methods and apparatus involve two keys to decode data that are generated during the encoding of the data. Since the underlying data is unique, each encryption is unique thereby making each key unique. The keys are stored on computing devices separate from one another, and the encrypted data, which maintains security until such time as the original data requires decoding. The separate devices may also include separate parties owning the devices. Because the keys can be several hundred to thousands of bits in length, its stored form may have padding bits to align with the file form of the encoded data.
In a representative embodiment, keys include a dictionary corresponding to symbols representing the data and a weighted path decoder that correlates the symbols of the dictionary to underlying original bits. To create the dictionary, an original data stream is arranged as a plurality of symbols. Of those symbols, all possible tuples are identified and the highest or most frequently occurring tuple is determined. A new symbol is created and substituted for each instance of the highest occurring tuple, which results in a new data stream. The dictionary includes every symbol. The new data stream is encoded with path weighted, Huffman encoding.
A “fast approximation” of compression of current data involves using information obtained from an earlier compression of similar data. Creating the two keys for the original data can also include creating one of the two keys as a master key for decoding a plurality of later-encoded files. A second key for the later-encoded files also works in conjunction with the master key during times of decoding the current data.
Executable instructions loaded on one or more computing devices for undertaking the foregoing are also contemplated as are computer program products available as a download or on a computer readable medium. The computer program products are also available for installation on a network appliance or an individual computing device.
These and other embodiments of the present invention will be set forth in the description which follows, and in part will become apparent to those of ordinary skill in the art by reference to the following description of the invention and referenced drawings or by practice of the invention. The claims, however, indicate the particularities of the invention.
The accompanying drawings incorporated in and forming a part of the specification, illustrate several aspects of the present invention, and together with the description serve to explain the principles of the invention. In the drawings:
b are data streams, tree diagrams and tables in accordance with the present invention relating to decompression of a compressed file;
In the following detailed description of the illustrated embodiments, reference is made to the accompanying drawings that form a part hereof, and in which is shown by way of illustration, specific embodiments in which the invention may be practiced. These embodiments are described in sufficient detail to enable those skilled in the art to practice the invention and like numerals represent like details in the various figures. Also, it is to be understood that other embodiments may be utilized and that process, mechanical, electrical, arrangement, software and/or other changes may be made without departing from the scope of the present invention. In accordance with the present invention, methods and apparatus are hereinafter described for optimizing data compression of digital data.
In a representative embodiment, compression occurs by finding highly occurring patterns in data streams, and replacing them with newly defined symbols that require less space to store than the original patterns. The goal is to eliminate as much redundancy from the digital data as possible. The end result has been shown by the inventor to achieve greater compression ratios on certain tested files than algorithms heretofore known.
In information theory, it is well understood that collections of data contain significant amounts of redundant information. Some redundancies are easily recognized, while others are difficult to observe. A familiar example of redundancy in the English language is the ordered pair of letters QU. When Q appears in written text, the reader anticipates and expects the letter U to follow, such as in the words queen, quick, acquit, and square. The letter U is mostly redundant information when it follows Q. Replacing a recurring pattern of adjacent characters with a single symbol can reduce the amount of space that it takes to store that information. For example, the ordered pair of letters QU can be replaced with a single memorable symbol when the text is stored. For this example, the small Greek letter alpha (α) is selected as the symbol, but any could be chosen that does not otherwise appear in the text under consideration. The resultant compressed text is one letter shorter for each occurrence of QU that is replaced with the single symbol (a). e.g., “αeen,” “αick,” “acαit,” and “sαare.” Such is also stored with a definition of the symbol alpha (α) in order to enable the original data to be restored. Later, the compressed text can be expanded by replacing the symbol with the original letters QU. There is no information loss. Also, this process can be repeated many times over to achieve further compression.
With reference to
Redundancy is the superfluous repetition of information. As demonstrated in the QU example above, adjacent characters in written text often form expected patterns that are easily detected. In contrast, digital data is stored as a series of bits where each bit can have only one of two values: off (represented as a zero (0)) and on (represented as a one (1)). Redundancies in digital data, such as long sequences of zeros or ones, are easily seen with the human eye. However, patterns are not obvious in highly complex digital data. The invention's methods and procedures identify these redundancies in stored information so that even highly complex data can be compressed. In turn, the techniques can be used to reduce, optimize, or eliminate redundancy by substituting the redundant information with symbols that take less space to store than the original information. When it is used to eliminate redundancy, the method might originally return compressed data that is larger than the original. This can occur because information about the symbols and how the symbols are encoded for storage must also be stored so that the data can be decompressed later. For example, compression of the word “queen” above resulted in the compressed word “αeen.” But a dictionary having the relationship QU=α also needed to be stored with the word “αeen,” which makes a “first pass” through the compression technique increase in size, not decrease. Eventually, however, further “passes” will stop increasing and decrease so rapidly, despite the presence of an ever-growing dictionary size, that compression ratios will be shown to greatly advance the state of the art. By automating the techniques with computer processors and computing software, compression will also occur exceptionally rapidly. In addition, the techniques herein will be shown to losslessly compress the data.
The following compression method iteratively substitutes symbols for highly occurring tuples in a data stream. An example of this process is provided later in the document.
The compression procedure will be performed on digital data. Each stored bit has a value of binary 0 or binary 1. This series of bits is referred to as the original digital data.
The original digital data is examined at the bit level. The series of bits is conceptually converted to a stream of characters, referred to as the data stream that represents the original data. The symbols 0 and 1 are used to represent the respective raw bit values in the new data stream. These symbols are considered to be atomic because all subsequently defined symbols represent tuples that are based on 0 and 1.
A dictionary is used to document the alphabet of symbols that are used in the data stream. Initially, the alphabet consists solely of the symbols 0 and 1.
The following tasks are performed iteratively on the data stream:
From
In the following example and with any data stream of digital data that can be compressed according to the techniques herein, two symbols (0 and 1) occur in the alphabet and are possibly the only symbols in the entire data stream. By examining them as “tuples,” the combination of the 0 and 1 as ordered pairs of adjoining characters reveals only four possible outcomes, i.e., a tuple represented by “00,” a tuple represented by “01,” a tuple represented by “10,” and a tuple represented by “11.”
With reference to
Determining the Most Highly Occurring Tuple
With
The process begins by examining the adjacent characters in position one and two of the data stream. Together, the pair of characters forms a tuple. Advance by one character in the stream and examine the characters in positions two and three. By incrementing through the data stream one character at a time, every combination of two adjacent characters in the data stream is examined and tallied against one of the tuples.
Sequences of repeated symbols create a special case that must be considered when tallying tuples. That is, when a symbol is repeated three or more times, skilled artisans might identify instances of a tuple that cannot exist because the symbols in the tuple belong to other instances of the same tuple. The number of actual tuples in this case is the number of times the symbol repeats divided by two.
For example, consider the data stream 14 in table 16 (
After the entire data stream has been examined, the final counts for each tuple are compared to determine which tuple occurs most frequently. In tabular form, the 0 followed by a 1 (tuple 0>1) occurs the most and is referenced at element 19 in table 22,
In the situation of a tie between two or more tuples, skilled artisans must choose between one of the tuples. For this, experimentation has revealed that choosing the tuple that contains the most complex characters usually results in the most efficient compression. If all tuples are equally complex, skilled artisans can choose any one of the tied tuples and define it as the most highly occurring.
The complexity of a tuple is determined by imagining that the symbols form the sides of a right triangle, and the complexity is a measure of the length of the hypotenuse of that triangle. Of course, the hypotenuse is related to the sum of the squares of the sides, as defined by the Pythagorean Theorem,
The tuple with the longest hypotenuse is considered the most complex tuple, and is the winner in the situation of a tie between the highest numbers of occurring tuples. The reason for this is that less-complex tuples in the situation of a tie are most likely to be resolved in subsequent passes in the decreasing order of their hypotenuse length. Should a tie in hypotenuse length occur, or a tie in complexity, evidence appears to suggest it does not make a difference which tuple is chosen as the most highly occurring.
For example, suppose that tuples 3>7, 4>4 and 1>5 each occur 356 times when counted (in a same pass). To determine the complexity of each tuple, use the tuple symbols as the two sides of a right triangle and calculate the hypotenuse,
Skilled artisans can also use the tuple array to visualize the hypotenuse by drawing lines in the columns and rows from the array origin to the tuple entry in the array, as shown in table 24 in
As before, a symbol stands for the two adjacent characters that form the tuple and skilled artisans select any new symbol they want provided it is not possibly found in the data stream elsewhere. Also, since the symbol and its definition are added to the alphabet, e.g., if “α=QU,” a dictionary grows by one new symbol in each pass through the data, as will be seen. A good example of a new symbol for use in the invention is a numerical character, sequentially selected, because numbers provide an unlimited source of unique symbols. In addition, reaching an optimized compression goal might take thousands (or even tens of thousands) of passes through the data stream and redundant symbols must be avoided relative to previous passes and future passes.
Replacing the Tuple with the New Symbol
Upon examining the data stream to find all occurrences of the highest occurring tuple, skilled artisans simply substitute the newly defined or newly created symbol for each occurrence of that tuple. Intuitively, substituting a single symbol for two characters compresses the data stream by one character for each occurrence of the tuple that is replaced.
To accomplish this, counting occurs for how many times that each of the symbols in the current alphabet occurs in the data stream. They then use the symbol count to apply an encoding scheme, such as a path-weighted Huffman coding scheme, to the alphabet. Huffman trees should be within the purview of the artisan's skill set.
The encoding assigns bits to each symbol in the current alphabet that actually appears in the data stream. That is, symbols with a count of zero occurrences are not encoded in the tree. Also, symbols might go “extinct” in the data stream as they are entirely consumed by yet more complex symbols, as will be seen. As a result, the Huffman code tree is rebuilt every time a new symbol is added to the dictionary. This means that the Huffman code for a given symbol can change with every pass. The encoded length of the data stream usually decreases with each pass.
The compressed file size is the total amount of space that it takes to store the Huffman-encoded data stream plus the information about the compression, such as information about the file, the dictionary, and the Huffman encoding tree. The compression information must be saved along with other information so that the encoded data can be decompressed later.
To accomplish this, artisans count the number of times that each symbol appears in the data stream. They also count the number of bits in the symbol's Huffman code to find its bit length. They then multiply the bit length by the symbol count to calculate the total bits needed to store all occurrences of the symbol. This is then repeated for each symbol. Thereafter, the total bit counts for all symbols are added to determine how many bits are needed to store only the compressed data. To determine the compressed file size, add the total bit count for the data to the number of bits required for the related compression information (the dictionary and the symbol-encoding information).
Determining Whether the Compression Goal has been Achieved
Substituting a tuple with a single symbol reduces the total number of characters in a data stream by one for each instance of a tuple that is replaced by a symbol. That is, for each instance, two existing characters are replaced with one new character. In a given pass, each instance of the tuple is replaced by a new symbol. There are three observed results:
By repeating the compression procedure a sufficient number of times, any series of characters can eventually be reduced to a single character. That “super-symbol” character conveys the entire meaning of the original text. However, the information about the symbols and encoding that is used to reach that final symbol is needed to restore the original data later. As the number of total characters in the text decreases with each repetition of the procedure, the number of symbols increases by one. With each new symbol, the size of the dictionary and the size of the Huffman tree increase, while the size of the data decreases relative to the number of instances of the tuple it replaces. It is possible that the information about the symbol takes more space to store than the original data it replaces. In order for the compressed file size to become smaller than the original data stream size, the text size must decrease faster than the size increases for the dictionary and the Huffman encoding information.
The question at hand is then, what is the optimal number of substitutions (new symbols) to make, and how should those substitutions be determined?
For each pass through the data stream, the encoded length of the text decreases, while the size of the dictionary and the Huffman tree increases. It has been observed that the compressed file size will reach a minimal value, and then increase. The increase occurs at some point because so few tuple replacements are done that the decrease in text size no longer outweighs the increase in size of the dictionary and Huffman tree.
The size of the compressed file does not decrease smoothly or steadily downward. As the compression process proceeds, the size might plateau or temporarily increase. In order to determine the true (global) minimum, it is necessary to continue some number of iterations past the each new (local) minimum point. This true minimal value represents the optimal compression for the data stream using this method.
Through experimentation, three conditions have been found that can be used to decide when to terminate the compression procedure: asymptotic reduction, observed low, and single character. Each method is described below. Other terminating conditions might be determined through further experimentation.
An asymptotic reduction is a concession to processing efficiency, rather than a completion of the procedure. When compressing larger files (100 kilobytes (KB) or greater), after several thousand passes, each additional pass produces only a very small additional compression. The compressed size is still trending downward, but at such a slow rate that additional compute time is not warranted.
Based on experimental results, the process is terminated if at least 1000 passes have been done, and less than 1% of additional data stream compression has occurred in the last 1000 passes. The previously noted minimum is therefore used as the optimum compressed file.
A reasonable number of passes have been performed on the data and in the last reasonable number of passes a new minimum encoded file size has not been detected. It appears that further passes only result in a larger encoded file size.
Based on experimental results, the process is terminated if at least 1000 passes have been done, and in the last 10% of the passes, a new low has not been established. The previously noted minimum is then used as the optimum compressed file.
The data stream has been reduced to exactly one character. This case occurs if the file is made up of data that can easily reduce to a single symbol, such a file filled with a repeating pattern. In cases like this, compression methods other than this one might result in smaller compressed file sizes.
The representative embodiment of the invention uses Huffman trees to encode the data stream that has been progressively shortened by tuple replacement, and balanced against the growth of the resultant Huffman tree and dictionary representation.
The average length of a Huffman encoded symbol depends upon two factors:
The average encoded symbol length grows in a somewhat stepwise fashion as more symbols are added to the dictionary. Because the Huffman tree is a binary tree, increases naturally occur as the number of symbols passes each level of the power of 2 (2, 4, 8, 16, 32, 64, etc.). At these points, the average number of bits needed to represent any given symbol normally increases by 1 bit, even though the number of characters that need to be encoded decreases. Subsequent compression passes usually overcome this temporary jump in encoded data stream length.
The second factor that affects the efficiency of Huffman coding is the distribution of the frequency of symbol use. If one symbol is used significantly more than any other, it can be assigned a shorter encoding representation, which results in a shorter encoded length overall, and results in maximum compression. The more frequently a symbol occurs, the shorter the encoded stream that replaces it. The less frequently a symbol occurs, the longer the encoded stream that replaces it.
If all symbols occur at approximately equal frequencies, the number of symbols has the greater effect than does the size of the encoded data stream. Supporting evidence is that maximum compression occurs when minimum redundancy occurs, that is, when the data appears random. This state of randomness occurs when every symbol occurs at the same frequency as any other symbol, and there is no discernable ordering to the symbols.
The method and procedure described in this document attempt to create a state of randomness in the data stream. By replacing highly occurring tuples with new symbols, eventually the frequency of all symbols present in the data stream becomes roughly equal. Similarly, the frequency of all tuples is also approximately equal. These two criteria (equal occurrence of every symbol and equal occurrence of ordered symbol groupings) is the definition of random data. Random data means no redundancy. No redundancy means maximum compression.
This method and procedure derives optimal compression from a combination of the two factors. It reduces the number of characters in the data stream by creating new symbols to replace highly occurring tuples. The frequency distribution of symbol occurrence in the data stream tends to equalize as oft occurring symbols are eliminated during tuple replacement. This has the effect of flattening the Huffman tree, minimizing average path lengths, and therefore, minimizing encoded data stream length. The number of newly created symbols is held to a minimum by measuring the increase in dictionary size against the decrease in encoded data stream size.
To demonstrate the compression procedure, a small data file contains the following simple ASCII characters:
aaaaaaaaaaaaaaaaaaaaaaaaaaabaaabaaaaaaaababbbbbb
Each character is stored as a sequence of eight bits that correlates to the ASCII code assigned to the character. The bit values for each character are:
a=01100001
b=01100010
The digital data that represents the file is the original data that we use for our compression procedure. Later, we want to decompress the compressed file to get back to the original data without data loss.
The digital data that represents the file is a series of bits, where each bit has a value of 0 or 1. We want to abstract the view of the bits by conceptually replacing them with symbols to form a sequential stream of characters, referred to as a data stream.
For our sample digital data, we create two new symbols called 0 and 1 to represent the raw bit values of 0 and 1, respectively. These two symbols form our initial alphabet, so we place them in the dictionary 26,
The data stream 30 in
Also, the characters in data stream 30 are separated with a space for user readability, but the space is not considered, just the characters. The space would not occur in computer memory either.
The data stream 30 of
For the initial pass, the original data stream and alphabet that were created in “Preparing the Data Stream” are obtained.
An easy way to identify all possible combinations of the characters in our current alphabet (at this time having 0 and 1) is to create a tuple array (table 35,
For example, the table 35 shows the tuple array for characters 0 and 1. In the cell for column 0 and row 0, the tuple is the ordered pair of 0 followed by 0. The shorthand notation of the tuple in the first cell is “0>0”. In the cell for column 0 and row 1, the tuple is 0 followed by 1, or “0>1”. In the cell for column 1 and row 0, the tuple is “1>0”. In the cell for column 1 and row 1, the tuple is “1>1”. (As skilled artisans will appreciate, most initial dictionaries and original tuple arrays will be identical to these. The reason is that computing data streams will all begin with a stream of 1's and 0's having two symbols only.)
After completion of the tuple array, we are ready to look for the tuples in the data stream 30,
For example, the first two characters in our sample data stream are 0 followed by 1. This matches the tuple 0>1, so we count that as one instance of the tuple. We step forward one character. The characters in positions two and three are 1 followed by 1, which matches the tuple 1>1. We count it as one instance of the 1>1 tuple. We consider the sequences of three or more zeros in the data stream (e.g., 01100001 . . . ) to determine the actual number of tuples for the 0>0 tuple. We repeat this process to the end of the data set with the count results in table 40,
Now that we have gathered statistics for how many times each tuple appears in the data stream 30, we compare the total counts for each tuple to determine which pattern is the most highly occurring. The tuple that occurs most frequently is a tie between a 1 followed by 0 (1>0), which occurs 96 times, and a 0 followed by 1 (0>1), which also occurs 96 times. As discussed above, skilled artisans then choose the most complex tuple and do so according to Pythagorean's Theorem. The sum of the squares for each tuple is the same, which is 1 (1+0) and 1 (0+1). Because they have the same complexity, it does not matter which one is chosen as the highest occurring. In this example, we will choose tuple 1>0.
We also count the number of instances of each of the symbols in the current alphabet as seen in table 41,
In this next pass, we replace the most highly occurring tuple from the previous pass with a new symbol, and then we determine whether we have achieved our compression goal.
We replace the most highly occurring tuple from the previous pass with a new symbol and add it to the alphabet. Continuing the example, we add a new symbol 2 to the dictionary and define it with the tuple defined as 1 followed by 0 (1>0). It is added to the dictionary 26′ as seen in
Replacing the Tuple with the New Symbol
In the original data stream 30, every instance of the tuple 1>0 is now replaced with the new, single symbol. In our example data stream 30,
After we compress the data stream by using the new symbol, we use a path-weighted Huffman coding scheme to assign bits to each symbol in the current alphabet.
To do this, we again count the number of instances of each of the symbols in the current alphabet (now having “0,” “1” and “2.”) The total symbol count in the data stream is 288 symbols as seen in table 41′,
Next, we use the counts to build a Huffman binary code tree. 1) List the symbols from highest count to lowest count. 2) Combine the counts for the two least frequently occurring symbols in the dictionary. This creates a node that has the value of the sum of the two counts. 3) Continue combining the two lowest counts in this manner until there is only one symbol remaining. This generates a Huffman binary code tree.
Finally, label the code tree paths with zeros (0s) and ones (1s). The Huffman coding scheme assigns shorter code words to the more frequent symbols, which helps reduce the size length of the encoded data. The Huffman code for a symbol is defined as the string of values associated with each path transition from the root to the symbol terminal node.
With reference to
In this compression procedure, we will re-build a Huffman code tree every time we add a symbol to the current dictionary. This means that the Huffman code for a given symbol can change with every compression pass.
From the Huffman tree, we use its code to evaluate the amount of space needed to store the compressed data as seen in table 52,
To know whether we achieved optimal compression, we must consider the total amount of space that it takes to store the compressed data plus the information about the compression that we need to store in order to decompress the data later. We also must store information about the file, the dictionary, and the Huffman tree. The table 57 in
Determining Whether the Compression Goal has been Achieved
Finally, we compare the original number of bits (384,
In early passes, however, we expect to see that the substitution requires more space than the original data because of the effect of carrying a dictionary, adding symbols, and building a tree. On the other hand, skilled artisans should observe an eventual reduction in the amount of space needed as the compression process continues. Namely, as the size of the data set decreases by the symbol replacement method, the size grows for the symbol dictionary and the Huffman tree information that we need for decompressing the data.
In this pass, we replace the most highly occurring tuple from the previous pass (pass 1) with still another new symbol, and then we determine whether we have achieved our compression goal.
As a result of the new symbol, the tuple array is expanded by adding the symbol that was created in the previous pass. Continuing our example, we add 2 as a first symbol and last symbol, and enter the tuples in the new cells of table 35′,
As before, the tuple array identifies the tuples that we look for and tally in our revised alphabet. As seen in table 40′,
We define still another new symbol “3” to represent the most highly occurring tuple 2>0, and add it to the dictionary 26″,
Replacing the Tuple with the New Symbol
In the data stream 30′,
As demonstrated above, we count the number of symbols in the data stream, and use the count to build a Huffman tree and code for the current alphabet. The total symbol count has been reduced from 288 to 234 (e.g., 88+48+40+58, but not including the EOF marker) as seen in table 41″,
We need to evaluate whether our substitution reduces the amount of space that it takes to store the data. As described above, we calculate the total bits needed (507) as in table 52′,
In table 57′,
Determining Whether the Compression Goal has been Achieved
Finally, we compare the original number of bits (384) to the current number of bits (545=507+38) that are needed for this compression pass. We find that it takes 141% or 1.41 times as many bits to store the compressed data as it took to store the original data. Compression is still not achieved and the amount of data in this technique is growing larger rather than smaller in comparison to the previous pass requiring 132%.
In this pass, we replace the most highly occurring tuple from the previous pass with a new symbol, and then we determine whether we have achieved our compression goal.
We expand the tuple array 35″,
The tuple array identifies the tuples that we look for and tally in our revised alphabet. In table 40″,
We define a new symbol 4 to represent the most highly occurring tuple 1>3, and add it to the dictionary 26″,
Replacing the Tuple with the New Symbol
In the data stream, we replace every instance of the most highly occurring tuple from the earlier data stream with the new single symbol. We replace the 48 instances of the 1>3 tuple with the symbol 4 and new data stream 30-4 is obtained,
We count the number of symbols in the data stream, and use the count to build a Huffman tree and code for the current alphabet as seen in table 41′″,
We need to evaluate whether our substitution reduces the amount of space that it takes to store the data. As seen in table 52″
In table 57′
Determining Whether the Compression Goal has been Achieved
Finally, we compare the original number of bits (384) to the current number of bits (382) that are needed for this compression pass. We find that it takes 0.99 times as many bits to store the compressed data as it took to store the original data. Compression is achieved.
In this pass, we replace the most highly occurring tuple from the previous pass with a new symbol, and then we determine whether we have achieved our compression goal.
We expand the tuple array 35′″,
The tuple array identifies the tuples that we look for and tally in our revised alphabet. In table 40′″,
We define a new symbol 5 to represent the 4>0 tuple, and add it to the dictionary 26-4,
Replacing the Tuple with the New Symbol
In the data stream, we replace every instance of the most highly occurring tuple with the new single symbol. We replace the 48 instances of the 40 tuple in data stream 30-4,
As demonstrated above, we count the number of symbols in the data stream, and use the count to build a Huffman tree and code for the current alphabet. There is no Huffman code assigned to the symbol 1 and the symbol 4 because there are no instances of these symbols in the compressed data in this pass. The total symbol count has been reduced from 184 to 136 (e.g., 40+0+40+8+0+48, but not including the EOF marker) as seen in table 41-4,
We need to evaluate whether our substitution reduces the amount of space that it takes to store the data. As seen in table 52′″,
As seen in table 57′″,
Determining Whether the Compression Goal has been Achieved
Finally, we compare the original number of bits (384) to the current number of bits (331) that are needed for this compression pass as seen in table 58′,
In this pass, we replace the most highly occurring tuple from the previous pass with a new symbol, and then we determine whether we have achieved our compression goal.
We expand the tuple array by adding the symbol that was created in the previous pass. We add the symbol 5 as a first symbol and last symbol, and enter the tuples in the new cells as seen in table 35-4,
The tuple array identifies the tuples that we look for and tally in our revised alphabet as seen in table 40-4,
We define a new symbol 6 to represent the most highly occurring tuple 2>5, and add it to the dictionary for the alphabet that was developed in the previous passes as seen in table 26-5,
Replacing the Tuple with the New Symbol
In the data stream, we replace every instance of the most highly occurring tuple with the new single symbol. We replace the 39 instances of the 2>5 tuple in data stream 30-5,
As demonstrated above, we count the number of symbols in the data stream, and use the count to build a Huffman tree and code for the current alphabet as seen in table 41-5,
We need to evaluate whether our substitution reduces the amount of space that it takes to store the data. As seen in table 52-4,
As seen in table 57-4,
Determining Whether the Compression Goal has been Achieved
Finally, we compare the original number of bits (384) to the current number of bits (246, or 187+59) that are needed for this compression pass as seen in table 58-4,
In this pass, we replace the most highly occurring tuple from the previous pass with a new symbol, and then we determine whether we have achieved our compression goal.
We expand the tuple array 35-5 by adding the symbol that was created in the previous pass as seen in
The tuple array identifies the tuples that we look for and tally in our revised alphabet. (Total Symbol Count=97) The tuple that occurs most frequently is the symbol 0 followed by symbol 6 (0>6). It occurs 39 times as seen in table 40-5,
We define a new symbol 7 to represent the 0>6 tuple, and add it to the dictionary for the alphabet that was developed in the previous passes as seen in table 26-6,
Replacing the Tuple with the New Symbol
In the data stream, we replace every instance of the most highly occurring tuple with the new single symbol. We replace the 39 instances of the 0>6 tuple in data stream 30-6,
As demonstrated above, we count the number of symbols in the data stream, and use the count to build a Huffman tree and code for the current alphabet as seen in table 41-6,
Because all the symbols 1, 4, and 6 have been removed from the data stream, there is no reason to express them in the encoding scheme of the Huffman tree 50′,
We need to evaluate whether our substitution reduces the amount of space that it takes to store the data. As seen in table 52-5,
As seen in table 57-5,
Determining Whether the Compression Goal has been Achieved
Finally, we compare the original number of bits (384) to the current number of bits (166, or 95+71) that are needed for this compression pass as seen in table 58-5,
Skilled artisans will also notice that overhead has been growing in size while the total number of bits is still decreasing. We repeat the procedure to determine if this is the optimum compressed file size. We compare the compression size for each subsequent pass to the first occurring lowest compressed file size. The chart 60,
With reference to table 61,
The information needed to decompress a file is usually written at the front of a compressed file, as well as to a separate dictionary only file. The compressed file contains information about the file, a coded representation of the Huffman tree that was used to compress the data, the dictionary of symbols that was created during the compression process, and the compressed data. The goal is to store the information and data in as few bits as possible.
This section describes a method and procedure for storing information in the compressed file.
The first four bits in the file are reserved for the version number of the file format, called the file type. This field allows flexibility for future versions of the software that might be used to write the encoded data to the storage media. The file type indicates which version of the software was used when we saved the file in order to allow the file to be decompressed later.
Four bits allows for up to 16 versions of the software. That is, binary numbers from 0000 to 1111 represent version numbers from 0 to 15. Currently, this field contains binary 0000.
The second four bits in the file are reserved for the maximum symbol width. This is the number of bits that it takes to store in binary form the largest symbol value. The actual value stored is four less than the number of bits required to store the largest symbol value in the compressed data. When we read the value, we add four to the stored number to get the actual maximum symbol width. This technique allows symbol values up to 20 bits. In practical terms, the value 2̂20 (2 raised to the 20th power) means that about million symbols can be used for encoding.
For example, if symbols 0-2000 might appear in the compressed file, the largest symbol ID (2000) would fit in a field containing 11 bits. Hence, a decimal 7 (binary 0111) would be stored in this field.
In the compression example, the maximum symbol width is the end-of-file symbol 8, which takes four bits in binary (1000). We subtract four, and store a value of 0000. When we decompress the data, we add four to zero to find the maximum symbol width of four bits. The symbol width is used to read the Huffman tree that immediately follows in the coded data stream.
We must store the path information for each symbol that appears in the Huffman tree and its value. To do this, we convert the symbol's digital value to binary. Each symbol will be stored in the same number of bits, as determined by the symbol with the largest digital value and stored as the just read “symbol width”.
In the example, the largest symbol in the dictionary in the Huffman encoded tree is the end-of-file symbol 8. The binary form of 8 is 1000, which takes 4 bits. We will store each of the symbol values in 4 bits.
To store a path, we will walk the Huffman tree in a method known as a pre-fix order recursive parse, where we visit each node of the tree in a known order. For each node in the tree one bit is stored. The value of the hit indicates if the node has children (1) or if it is a leaf with no children (0). If it is a leaf, we also store the symbol value. We start at the root and follow the left branch down first. We visit each node only once. When we return to the root, we follow the right branch down, and repeat the process for the right branch.
In the following example, the Huffman encoded tree is redrawn as 50-2 to illustrate the prefix-order parse, where nodes with children are labeled as 1, and leaf nodes are labeled as 0 as seen in
The discovered paths and symbols are stored in the binary form in the order in which they are discovered in this method of parsing. Write the following bit string to the file, where the bits displayed in bold/underline represent the path, and the value of the 0 node are displayed without bold/underline. The spaces are added for readability; they are not written to media.
110 0101 110 0000 10 1000 0 0010 0 0011 0 0111
The dictionary information is stored as sequential first/last definitions, starting with the two symbols that define the symbol 2. We can observe the following characteristics of the dictionary:
Because the symbol represents a tuple made up of lower-level symbols, we will increase the bit width at the next higher symbol value; that is, at 3, 5, 9, and 17, instead of at 2, 4, 8, and 16.
We use this information to minimize the amount of space needed to store the dictionary. We store the binary values for the tuple in the order of first and last, and use only the number of bits needed for the values.
Three dictionary instances have special meanings. The 0 and 1 symbols represent the atomic symbols of data binary 0 binary 1, respectively. The last structure in the array represents the end-of-file (EOF) symbol, which does not have any component pieces. The EOF symbol is always assigned a value that is one number higher than the last symbol found in the data stream.
Continuing our compression example, the table 63,
Write the following bit string to the file. The spaces are added for readability; they are not written to media.
10 1000 0111 100000 010101 000110
To store the encoded data, we replace the symbol with its matching Huffman code and write the bits to the media. At the end of the encoded bit string, we write the EOF symbol. In our example, the final compressed symbol string is seen again as 30-7,
The Huffman code for the optimal compression is shown in table 67,
As we step through the data stream, we replace the symbol with the Huffman coded bits as seen at string 68,
The compressed bit string for the data, without spaces is:
010000111111111111111111111111111011001110110011111111011001011000110001 10001100011000101101010
As summarized in the diagram 69,
In the example, the bits 70 of
The process of decompression unpacks the data from the beginning of the file 69,
Read the first four bits of the file to determine the file format version.
Read the next four bits in the file, and then add four to the value to determine the maximum symbol width. This value is needed to read the Huffman tree information.
Reconstruct the Huffman tree. Each 1 bit represents a node with two children. Each 0 bit represents a leaf node, and it is immediately followed by the symbol value. Read the number of bits for the symbol using the maximum symbol width.
In the example, the stored string for Huffman is:
11001011100000101000000100001100111
With reference to
To reconstruct the dictionary from file 69, read the values for the pairs of tuples and populate the table. The values of 0 and 1 are known, so they are automatically included. The bits are read in groups based on the number of bits per symbol at that level as seen in table 72,
In our example, the following bits were stored in the file:
1010000111101000010101000110
We read the numbers in pairs, according to the bits per symbol, where the pairs represent the numbers that define symbols in the dictionary:
We convert each binary number to a decimal number:
We identify the decimal values as the tuple definitions for the symbols:
We populate the dictionary with these definitions as seen in table 73,
We use the tuples that are defined in the re-constructed dictionary to build the Huffman decode tree. Let's decode the example dictionary to demonstrate the process. The diagram 74 in
Start with symbols 0 and 1. These are the atomic elements, so there is no related tuple. The symbol 0 is a left branch from the root. The symbol 1 is a right branch. (Left and right are relative to the node as you are facing the diagram—that is, on your left and on your right.) The atomic elements are each represented by a single bit, so the binary path and the original path are the same. Record the original bits 0 and 1 in the decode table.
Symbol 2 is defined as the tuple 1>0 (symbol 1 followed by symbol 0). In the decode tree, go to the node for symbol 1, then add a path that represents symbol 0. That is, add a left branch at node 1. The terminating node is the symbol 2. Traverse the path from the root to the leaf to read the branch paths of left (L) and right (R). Replace each left branch with a 0 and each right path with a 1 to view the binary forum of the path as LR, or binary 10.
Symbol 3 is defined as the tuple 2>0. In the decode tree, go to the node for symbol 2, then add a path that represents symbol 0. That is, add a left branch at node 2. The terminating node is the symbol 3. Traverse the path from the root to the leaf to read the branch path of RLL. Replace each left branch with a 0 and each right path with a 1 to view the binary form of the path as 100.
Symbol 4 is defined as the tuple 1>3. In the decode tree, go to the node for symbol 1, then add a path that represents symbol 3. From the root to the node for symbol 3, the path is RLL. At symbol 1, add the RLL path. The terminating node is symbol 4. Traverse the path from the root to the leaf to read the path of RRLL, which translates to the binary format of 1100.
Symbol 5 is defined as the tuple 4>0. In the decode tree, go to the node for symbol 4, then add a path that represents symbol 0. At symbol 4, add the L path. The terminating node is symbol 5. Traverse the path from the root to the leaf to read the path of RRLLL, which translates to the binary format of 11000.
Symbol 6 is defined as the tuple 2>5. In the decode tree, go to the node for symbol 2, then add a path that represents symbol 5. From the root to the node for symbol 5, the path is RRLLL. The terminating node is symbol 6. Traverse the path from the root to the leaf to read the path of RLRRLLL, which translates to the binary format of 1011000.
Symbol 7 is defined as the tuple 0>6. In the decode tree, go to the node for symbol 0, then add a path that represents symbol 6. From the root to the node for symbol 6, the path is RLRRLLL. The terminating node is symbol 7. Traverse the path from the root to the leaf to read the path of LRLRRLLL, which translates to the binary format of 01011000.
To decompress the data, we need the reconstructed Huffman tree and the decode table that maps the symbols to their original bits as seen at 75,
The compressed file data bits are:
010000111111111111111111111111111011001110110011111111011001011000110001 10001100011000101101010
For example, the first four bits of encoded data 0100 takes us to symbol 0 in the Huffman tree, as illustrated in the diagram 76,
In the diagram 77 in
In the diagram 78,
The next symbol we discover is with bits 011. We follow these bits in the Huffman tree in diagram 79,
We continue the decoding and replacement process to discover the symbol 2 near the end of the stream with bits 01011, as illustrated in diagram 80,
The final unique sequence of bits that we discover is the end-of-file sequence of 01010, as illustrated in diagram 81,
Altogether, the unpacking of compressed bits recovers the original bits of the original data stream in the order of diagram 82 spread across two
With reference to
An intervening Xen or other hypervisor layer 150, also known as a “virtual machine monitor,” or virtualization manager, serves as a virtual interface to the hardware and virtualizes the hardware. It is also the lowest and most privileged layer and performs scheduling control between the virtual machines as they task the resources of the hardware platform, e.g., memory, processor, storage, network (N) (by way of network interface cards, for example), etc. The hypervisor also manages conflicts, among other things, caused by operating system access to privileged machine instructions. The hypervisor can also be type 1 (native) or type 2 (hosted). According to various partitions, the operating systems, applications, application data, boot data, or other data, executable instructions, etc., of the machines are virtually stored on the resources of the hardware platform. Alternatively, the computing system environment is not a virtual environment at all, but a more traditional environment lacking a hypervisor, and partitioned virtual domains. Also, the environment could include dedicated services or those hosted on other devices.
In any embodiment, the representative computing device 120 is arranged to communicate 180 with one or more other computing devices or networks. In this regard, the devices may use wired, wireless or combined connections to other devices/networks and may be direct or indirect connections. If direct, they typify connections within physical or network proximity (e.g., intranet). If indirect, they typify connections such as those found with the internet, satellites, radio transmissions, or the like. The connections may also be local area networks (LAN), wide area networks (WAN), metro area networks (MAN), etc., that are presented by way of example and not limitation. The topology is also any of a variety, such as ring, star, bridged, cascaded, meshed, or other known or hereinafter invented arrangement.
In still other embodiments, skilled artisans will appreciate that enterprises can implement some or all of the foregoing with humans, such as system administrators, computing devices, executable code, or combinations thereof. In turn, methods and apparatus of the invention further contemplate computer executable instructions, e.g., code or software, as part of computer program products on readable media, e.g., disks for insertion in a drive of a computing device 120, or available as downloads or direct use from an upstream computing device. When described in the context of such computer program products, it is denoted that items thereof, such as modules, routines, programs, objects, components, data structures, etc., perform particular tasks or implement particular abstract data types within various structures of the computing system which cause a certain function or group of function, and such are well known in the art.
While the foregoing produces a well-compressed output file, e.g.,
The definitions from
Broadly, the “fast approximation” hereafter 1) greatly reduces the processing time needed to compress a file using the techniques above, and 2) creates and uses a decode tree to identify the most complex possible pattern from an input bit stream that matches previously defined patterns. Similar to earlier embodiments, this encoding method requires repetitive computation that can be automated by computer software. The following discusses the logical processes involved.
Instead of using the iterative process of discovery of the optimal set of symbols, above, the following uses the symbols that were previously created for another file that contains patterns significantly similar to those of the file under consideration. In a high-level flow, the process involves the following tasks:
The objective of the fast approximation method is to take advantage of the key information in an optimally compressed file that was created by using the techniques above. In its uncompressed form of original data, the compressed file should contain data patterns that are significantly similar to the patterns in the current file under consideration for compression. The effectiveness of the resultant compression depends on how similar a related file's patterns are to the original file's patterns. The way a skilled artisan recognizes a similar file is that similar bit patterns are found in the originally compressed and new file yet to be compressed. It can be theorized a priori that files are likely similar if they have similar formatting (e.g., text, audio, image, powerpoint, spreadsheet, etc), topic content, tools used to create the files, file type, etc. Conclusive evidence of similar bit patterns is that similar compression ratios will occur on both files (i.e. original file compresses to 35% of original size, while target file also compresses to about 35% of original size). It should be noted that similar file sizes are not a requisite for similar patterns being present in both files.
With reference to
From the key information 200, read and unpack the File Type, Maximum Symbol Width, Huffman Tree, and Dictionary fields.
Create a pattern decode tree using the symbol dictionary retrieved from the key information. Each symbol represents a bit pattern from the original data stream. We determine what those bits are by building a decode tree, and then parsing the tree to read the bit patterns for each symbol.
We use the tuples that are defined in the re-constructed dictionary to build the decode tree. The pattern decode tree is formed as a tree that begins at the root and branches downward. A terminal node represents a symbol ID value. A transition node is a placeholder for a bit that leads to terminal nodes.
Read the bit stream of the current file one bit at a time. As the data stream is parsed from left to right, the paths in the decode tree are traversed to detect patterns in the data that match symbols in the original dictionary.
Starting from the root of the pattern decode tree, use the value of each input bit to determine the descent path thru the pattern decode tree. A “0” indicates a path down and to the left, while a 1″ indicates a path down and to the right. Continue descending through the decode tree until there is no more descent path available. This can occur because a branch left is indicated with no left branch available, or a branch right is indicated with no right branch available.
When the end of the descent path is reached, one of the following occurs:
Return to the root of the decode tree and continue with the next bit in the data stream to find the next symbol.
Repeat this process until all of the bits in the stream have been matched to patterns in the decode tree. When done, there exists a list of all of the symbols that occur in the bit stream and the frequency of occurrence for each symbol.
Use the frequency information to create a Huffman encoding tree for the symbols that occur in the current file. Include the end-of-file (EOF) symbol when constructing the tree and determining the code.
Use the Huffman tree for the current file to encode its data. The information needed to decompress the file is written at the front of the compressed file, as well as to a separate dictionary only file. The compressed file contains:
This example uses the key information 200 from a previously created but related compressed file to approximate the symbols needed to compress a different file.
With reference to table 202,
Construct the Decode Tree from the Dictionary
With reference to
Start with symbols 0 and 1. These are the atomic elements, by definition, so there is no related tuple as in the dictionary of
Symbol 2 is defined from the dictionary as the tuple 1>0 (symbol 1 followed by symbol 0). In the decode tree 212, go to the node for symbol 1 (which is transition node 205 followed by a right path R and ending in a terminal node 206, or arrow 214), then add a path that represents symbol 0 (which is transition node 205 followed by a left path L and ending in a terminal node 206, or path 216). That is, you add a left branch at node 1. The terminating node 220 is the symbol 2. Traverse the path from the root to the leaf to read the branch paths of right (R) and left (L). Replace each left branch with a 0 and each right path with a 1 to view the binary form of the path as RL, or binary 10 as in decode table 210.
Symbol 3 is defined as the tuple 2>0. In its decode tree 230, it is the same as the decode tree for symbol 2, which is decode tree 212, followed by the “0.” Particularly, in tree 230, go to the node for symbol 2, then add a path that represents symbol 0. That is, you add a left branch (e.g., arrow 216) at node 2. The terminating node is the symbol 3. Traverse the path from the root to the leaf to read the branch path of RLL. Replace each left branch with a 0 and each right path with a 1 to view the binary format of 100 as in the decode table.
Similarly, the other symbols are defined with decode trees building on the decode trees for other symbols. In particular, they are as follows:
Symbol 4 from the dictionary is defined as the tuple 1>3. In its decode tree, go to the node for symbol 1, then add a path that represents symbol 3. From the root to the node for symbol 3, the path is RLL. At symbol 1, add the RLL path. The terminating node is symbol 4. Traverse the path from the root to the leaf to read the path of RRLL, which translates to the binary format of 1100 as in the decode table.
Symbol 5 is defined as the tuple 4>0. In its decode tree, go to the node for symbol 4, then add a path that represents symbol 0. At symbol 4, add the L path. The terminating node is symbol 5. Traverse the path from the root to the leaf to read the path of RRLLL, which translates to the binary format of 11000.
Symbol 6 is defined as the tuple 5>3. In its decode tree, go to the node for symbol 5, then add a path that represents symbol 3. The terminating node is symbol 6. Traverse the path from the root to the leaf to read the path of RRLLLRLL, which translates to the binary format of 11000100.
Symbol 7 is defined from the dictionary as the tuple 5>0. In its decode tree, go to the node for symbol 5, then add a path that represents symbol 0. From the root to the node for symbol 5, the path is RRLLL. Add a left branch. The terminating node is symbol 7. Traverse the path from the root to the leaf to read the path of RRLLLL, which translates to the binary format of 110000.
Finally, symbol 8 is defined in the dictionary as the tuple 7>2. In its decode tree, go to the node for symbol 7, then add a path that represents symbol 2. From the root to the node for symbol 7, the path is RRLLLL. Add a RL path for symbol 2. The terminating node is symbol 8. Traverse the path from the root to the leaf to read the path of RRLLLLRL, which translates to the binary format of 11000010.
The final decode tree for all symbols put together in a single tree is element 240,
For this example, the sample or “current file” to be compressed is similar to the one earlier compressed who's key information 200,
01 10000101 10001001 10000101 10001001 10000101 10000101 10001001 10000101 100010 01 10000101 10000101 10001001 10000101 10001001 10000101 10001001 10000101 100010 01 10001001 10001001 10001001 10001001 10000101 10000101 10001001 10000101 100010 01 10000101 100010
We step through the stream one bit at a time to match patterns in the stream to the known symbols from the dictionary 200,
Return to the root node of the Decode Tree, and begin looking for the next symbol again starting with the last unused input stream bit, e.g., the bit “1” at position 255,
From here, the frequency of occurrence of each of the symbols in the new bit stream is counted. For example, the symbols “0” and 2″ are each found occurring once at the beginning and end of the new bit stream. Similarly, the symbol “5” is counted once just before the symbol “2.” Each of the symbols “6” and “8” are counted fourteen times in the middle of the new bit stream for a total of thirty-one symbols. Its result is shown in table 275,
From the symbol “counts” in
To construct the tree 280, list first the symbols from highest count to lowest count. In this example, the symbol “8” and symbol “6” tied with a count of fourteen and are each listed highest on the tree. On the other hand, the least counted symbols were each of symbol “0,” “2,” “5,” and the EOF. Combine the counts for the two least frequently occurring symbols in the dictionary. This creates a node that has the value of the sum of the two counts. In this example, the EOF and 0 are combined into a single node 281 as are the symbols 2 and 5 at node 283. Together, all four of these symbols combine into a node 285. Continue combining the two lowest counts in this manner until there is only one symbol remaining. This generates a Huffman binary code tree.
Label the code tree paths with zeros (0s) and ones (1s). To encode a symbol, parse from the root to the symbol. Each left and down path represents a 0 in the Huffman code. Each right and down path represents a 1 in the Huffman code. The Huffman coding scheme assigns shorter code words to the more frequent symbols, which helps reduce the size length of the encoded data. The Huffman code for a symbol is defined as the string of values associated with each path transition from the root to the symbol terminal node.
With reference to
The diagram in
1001 0 11 0 11 0 0 11 0 11 0 0 11 0 11 0 11 0 11 11 11 11 11 0 0 11 0 11 0 1011 1010 1000
Spaces are shown between the coded bits for readability; the spaces are not written to media. Also, the code for the EOF symbol (1000) is placed at the end of the encoded data and shown in underline.
With reference to
In still another alternate embodiment, the following describes technology to produce two keys that are applied together to decrypt an encrypted file. The keys are related, but one key cannot be used to create the other. Rather, the keys are mathematically independent of each other. During use, both keys must be available to reveal a message that has been locked, or encrypted. The information in the two keys is generated by the compression procedure above, e.g.,
In a typical encryption key, the key is a sequence of bytes or bits that are generated by running a known encryption algorithm. The algorithm determines the length of a key. For example, the popular algorithm Advanced Encryption Standard (AES) uses a symmetric key method and has key sizes of 128, 192, or 256 bits (that is, the key length is up to 32 bytes).
In the present embodiment, both key bit streams are naturally rather large (usually several hundred to several thousand bytes), so the key space in storage is also very large. Hence, the method provides reasonably high security.
As before, there are several methods of generating keys for encryption. For example, a known algorithm might be applied to a special secure password or to a randomly generated sequence of bits in order to generate the key.
The two-keys discussed herein, in contrast, use the data itself to generate the information in the two keys. Thus, each encryption is unique (since the underlying data is unique), and the keys are unique to the data that was used to create them. The key information can be several hundred to several thousand bits in length.
This section describes how to produce the two keys for files compressed by using either of the following compression/decompression procedures for the full technique above or those in the fast approximation embodiment.
With reference to
The Huffman tree, 300
The dictionary, 302
The encoded data, 304
In turn, the three components are stored separately. The first two components 300, 302, become the two keys for the encoded data 310. The two keys are distributed to independent key holders, such as first and second computing devices, while the compressed/encrypted data is held in any convenient, even public, storage place. Intuitively, then, the encoded data 304 is protected because it cannot be decoded unless both the Huffman tree 300 and the dictionary 302 are available and used simultaneously on the data. From above, the dictionary appears as a description of symbols and their relationships to tuples of symbols, but otherwise has no relation to a symbol's underlying original bits of data. The Huffman tree, on the other hand, is that which relates the tuples to a decode table having the actual relationship of original bits relative to the symbols. With these being separated now, and distributed to independent parties, the encoded data is protected until such time as both the dictionary and Huffman tree are brought and used together.
In addition, the data compressed by using these keys is protected within the compressed data stream. As before, the compressed data stream includes the Huffman encoded data, the encoded end of file (EOF) symbol, and pad bits to align with the byte for storage. When separating the key information, the File Type and Symbol Width fields are stored with the Huffman tree information. Alternatively, the other component 302 might include the file type and symbol width. Also, both keys might be padded with bits at the end to byte align the bit stream for storage (“Pad bits to Byte Align”). In this manner, the forms of the files are kept similarly in storage.
Producing Two Keys for a File Compressed with Fast Approximation
With reference to
The Huffman tree, 300′
The dictionary, 302′
The encoded data, 304′
In turn, the three components are stored separately. The first two components 300′, 302′, become the two keys for the encoded data 310′. The two keys are distributed to independent key holders, such as first and second computing devices, while the compressed/encrypted data is held in any convenient, even public, storage place. Intuitively, then, the encoded data 304′ is protected because it cannot be decoded unless both the Huffman tree 300′ and the dictionary 302′ are available and used simultaneously on the data. From above, the dictionary appears as a description of symbols and their relationships to tuples of symbols, but otherwise has no relation to a symbol's underlying original bits of data. The Huffman tree, on the other hand, is that which relates the tuples to a decode table having the actual relationship of original bits relative to the symbols. With these being separated now, and distributed to independent parties, the encoded data is protected until such time as both the dictionary and Huffman tree are brought and used together.
In addition, the data compressed by using these keys is protected within the compressed data stream. As before, the compressed data stream includes the Huffman encoded data, the encoded end of file (EOF) symbol, and pad bits to align with the byte for storage. When separating the key information, the File Type and Symbol Width fields are stored with the Huffman tree information. Alternatively, the other component 302′ might include the file type and symbol width. Also, both keys might be padded with bits at the end to byte align the bit stream for storage (“Pad bits to Byte Align”). In this manner, the forms of the files are kept similarly in storage.
In this scenario, skilled artisans should remember that files created with fast approximation techniques, e.g., file 69′,
Also, the fast approximation method results in the original file's key 2 being a master key that applies to multiple files (later encoded having data similar to the original document) 312-a, 312, b, 312-c, and an individual key (key 1) therefore.
The compression methods for full compression or fast approximation offer different benefits. Some of their features are summarized in table 320,
As before, when the time comes for the compressed/encrypted data to be revealed, the two keys and the data must be simultaneously presented to the decompression/decryption method. For this, the Huffman tree information of key 1 can be unpacked and constructed by using the pre-fix order method described above in the section entitled “Decompressing the Compressed File.” When the pre-fix order process returns to the root position, the Huffman tree is done unpacking for purposes of decrypting/uncompressing the encoded data. The pad bits are discarded.
The dictionary information for key 2 can be unpacked by reading the values for the pairs of tuples and populating the tuples table, as also described above in the section entitled “Decompressing the Compressed File.” The End of File symbol (as determined from reconstructing the Huffman tree with the first key) helps identify when all of the symbols in the dictionary have been recovered from the dictionary key. The pad bits are similarly discarded.
After unpacking the information in the two keys, the encoded data can be decrypted as earlier described.
The foregoing has been described in terms of specific embodiments, but one of ordinary skill in the art will recognize that additional embodiments are possible without departing from its teachings. This detailed description, therefore, and particularly the specific details of the exemplary embodiments disclosed, is given primarily for clarity of understanding, and no unnecessary limitations are to be implied, for modifications will become evident to those skilled in the art upon reading this disclosure and may be made without departing from the spirit or scope of the invention. Relatively apparent modifications, of course, include combining the various features of one or more figures with the features of one or more of the other figures.
This utility application claims priority to U.S. Provisional Application Ser. Nos. 61/236,571 and 61/271,079, filed Aug. 25, 2009, and Jul. 16, 2009, respectively. Their contents are expressly incorporated herein as if set forth herein.
| Number | Date | Country | |
|---|---|---|---|
| 61236571 | Aug 2009 | US | |
| 61271079 | Jul 2009 | US |
