Many applications exist for step-up voltage converters capable of delivering high-currents. One such application is the need to drive LEDs at high currents for the camera flash function. The brightness of white LEDs is proportional to current. Currents may range from a few hundred milliamperes to several amperes. At high currents the voltage drop across a white LED can be more than three to four volts. Special high-intensity LEDs for high brightness camera flash applications exhibit even higher voltages, voltages higher than the voltage of a single cell lithium ion battery. In order to drive such high brightness LEDs, the battery voltage must be stepped up to a higher potential.
While charge pump converters can be used up to one half ampere, the input current of a charge pump is multiplied by the voltage conversion ratio. A doubler charge pump produces an output voltage double its input but requires an input current at least double its output. So at one-half ampere LED current, the input current of the charge pump LED driver exceeds one ampere. At higher currents, the input current demand of a charge pump becomes excessive. In such instances a boost type switching regulator is preferred.
As shown in
The converter alternates between conduction states (1) and (2) until the boost output voltage Vboost reaches its target value set by PWM controller 10 reacting in response to feedback voltage VFB. This pre-charging operating sequence is illustrated by voltage ramp 21 illustrated in graph 20 of
At time t2, flash controller 9 turns on power MOSFET 7 and current flows from the boost converter's output through LED 6, conducting MOSFET 7, and current setting resistor 8 to ground along the conductor path designated by the dashed arrow (3). Assuming MOSFET 7 has an on-state resistance of RDS(on) and resistor Rset has a resistance substantially greater than the MOSFET's on-resistance. The current flowing during this interval is then given by the relation
Assuming that Vf(LED) at high current is 4.5V, that Vboost is biased to 4.6V, and using a resistor value of Rset=0.1Ω, then ILED=1 A.
Although a 1 A current is thirty times the current normally used for lighting LEDs, high brightness flash LEDs typically comprise an array of parallel LEDs. Moreover in a camera flash application, the LED conduction duration is limited to a few hundred milliseconds. By controlling the flash time, the total energy dissipated by the LEDs is limited and the LED array is not damaged.
During the flash interval, the ILED current 24 decays in proportion to the sagging Vboost voltage 23 present on capacitor 5. During the flash interval, converter 1 operating in fixed frequency operation naturally alternates between discharge path (3) and magnetizing condition (1), with the converter attempting to minimize the voltage sag on inductor 5. The degree of voltage sag depends on the magnitude of inductance in inductor 3 and the magnitude of capacitance of capacitor 5.
Operating in variable frequency mode during the flash, converter 1 may remain in the discharging state with conduction path (3) for an extended duration. If the inductor current drops too low, however, the LED brightness will fall to unacceptable brightness levels. To avoid this problem even in a variable frequency mode, converter 1 must occasionally return to condition (1) to magnetize inductor 3 and to, at least in part, restore its current.
At time t3, when the flash interval is complete, MOSFET 7 is turned off and ILED drops to zero, during which the converter returns to alternating between states (1) and (2). With ILED=0, the value of Vboost recovers back to its ready state, as shown at time t4.
One major limitation of an inductive boost converter is its need to draw high currents from the battery. In
The input power delivered to boost converter 34 is equal to the power delivered to the load and any additional power needed to operate converter 35. Assuming as a best case 100% efficiency of boost converter 35 then its power input must equal its power output so that
P
IN
=P
OUT
=I
batt
V
batt
=V
boost
I
boost
If the charge stored on output capacitor 37 negligible compared to the total current required to fire flash LED 38 then it follows Iboost≈ILED and therefore
Since by definition for a boost converter Vboost>Vbatt, then the converter's average input must exceed the current load current ICED during the flash. For a 5V LED and a single cell lithium ion battery at 3.6V, the average input current to the converter is roughly 40% higher. So to achieve an average of 1 A an LED flash demands a 1.4 A current from the battery.
Referring again to
V
batt
=V
cell
−R
batt
I
batt
If, for example a 1.4 A current flows through a 500 mΩ pack, a 700 mV volt drop will occur in the pack. If the battery's cell is partially discharged to 3.5V, a sudden current spike to 1.4 A can cause the battery's terminal voltage to drop 2.8V. Such a transient is illustrated in graph 45 of
Aside from issues of voltage transients from high currents, the overall power demanded by the LED during a camera flash puts additional requirements on a boost converter's operation.
LED Drive Energy and Power Requirements
The power requirements of the boost converter driving high current LEDs as a camera flash is given by the relation
P=I
LED
·V
ƒ(LED)
=P
light
+P
heat
The total power consumed by the LED is then 1 A times 4.5V or 4.5 W. As an energy conversion device, the optical efficiency of the LED is ηλ, then
P
heat=(100%−ηλ)(ILED·Vƒ(LED))
and assuming a 60% energy conversion efficiency Pheat=40% (4.5 W)=1.8 W of peak thermal dissipation divided among several LEDs in the array. Since the flash duty factor is very low, typically less than a few percent, the average power dissipation is only hundred milliwatts so that overheating and excessive LED temperatures are not critical.
Furthermore the thermal energy absorbed by the LED in a single-pulse is of limited duration, the LED is not damaged during a single pulse even at high currents. The absorbed thermal energy is given by the relation
E
heat
=P
heat
·t
flash=(100%−ηλ)(ILED·Vƒ(LED))tflash
For example if the flash time tflash is several hundred milliseconds, e.g. 200 milliseconds, the total energy dissipated as heat is E=(1.8 W)(0.2 s)=360 mJ, not a large amount of energy for a short transient pulse.
The total energy supplied by the converter to the LED during the flash is larger, however, since it includes energy converted to the light output as well as to Joule heating. Given
E=P
total
t
flash=(ILED·Vƒ(LED))tflash
Then at 4.5V and 1 A, a 200 msec pulse requires a boost converter to deliver 900 mJ to power the flash operation.
In a boost converter 1 the energy stored in the output capacitor 5 is
Assuming C=4.7 uF, the capacitor stores only around 50 μj. The energy stored in inductor 3 is given by
At 1 A, the energy stored in a 4.7 uH inductor is then only 2.3 μj. Both inductor 3 and capacitor 5 store too little energy to power the entire duration of flash. This means that using reasonable values of inductance and capacitance there is not enough energy stored in a boost converter to power the entire flash and instead the switching regulator must keep switching and transferring energy during the entire flash pulse. Operation of a switching converter however continuously draws power from the battery at an average current higher than the flash LED's current.
Super-Cap Flash Technique
To avoid the need for drawing current from the battery during a flash, a large storage capacitor can be used to supply the entire flash transient. Such a solution 50 is illustrated in
To estimate the magnitude of the energy that must be stored on super-cap 55, the relation
Super capacitors however can only be charged to low voltages, e.g. to 4V without damaging their internal dielectrics. Assuming the flash energy requirement of 900 mJ calculated previously the resulting capacitance required is then approximately 110 mF, i.e. over one-tenth of a Farad, four orders of magnitude greater than normal capacitors. Super capacitors up to one Farad are now commercially available. Several disadvantages of super capacitors, however, are that they are expensive and large, possibly too large to be useful in space conscious digital still cameras and camera phones.
Another complication of super-caps is that they cannot be charged directly from the battery. If an uncharged super-cap is connected directly across a battery, it behaves identically to a dead short and may damage the battery. Instead the charging current must be regulated by additional circuitry 54, adding and cost and complexity to the super-cap camera flash LED solution.
So while the super-cap solves the issue of drawing excessive currents from a battery pack during an LED camera flash it is expensive, large, and complex to operate. What is needed is a means to drive an LED at high currents and at voltages higher than the battery's voltage without drawing high or excessive currents from the battery during flash operation.
A switch-mode boost converter and step-up voltage regulator capable of delivering high output currents with low input currents is disclosed. The converter comprises two or more inductors and a switching network. The switching network allows the inductors to be alternately connected in a magnetizing configuration and a charge transfer configuration. For the magnetizing configuration, the inductors are connected in series between an input supply and ground. For the charge transfer configuration, each inductor is connected between ground and the parallel combination of an output capacitor and load. Operation of the converter involves alternating between the magnetizing and charge transferring configurations to transfer energy to the output capacitor and load under duty factor or variable frequency control using feedback of the output voltage to control timing of the switching.
In the case where two inductors are used, a first switch typically connects the input supply to a node VZ. The first inductor connects the node VZ to a node VY. A second switch connects the node VY to a node VW. The second inductor connects the node VW to a node VX. A third switch connects the node VX to ground. When the first, second and third switches are ON, the two inductors are connected in series between the input supply and ground for the magnetizing configuration.
A fourth switch connects the node VZ to ground and a fifth switch connects the node VW to ground. When these two switches are ON and the first through third switches are OFF, each inductor is connected between ground and the parallel combination of an output capacitor and load for the charge transfer configuration.
Diodes are placed between the inductors and the load to prevent current from flowing out of the load into ground through the two inductors. In some embodiments, these diodes may be replaced with switches that are driven out of phase with the switches which interconnect the inductors (e.g., the first through third switch described above). The use of switches effectively eliminates the voltage drop associated with the use of diodes.
For some embodiments one of the inductors remains connected to the input supply during charge transfer and magnetizing configurations. The remaining inductors function as previously described and are grounded during charge transfer. For such an embodiment, the first inductor connects the input supply to a node VY. A first switch connects the node VY to a node VW. The second inductor connects the node VW to a node VX. A second switch connects the node VX to ground. When the first and second and third switches are ON, the two inductors are connected in series between the input supply and ground for the magnetizing configuration.
A third switch connects the node VW to ground. When this switch is ON and the first and second switches are OFF, each inductor is connected between ground and the parallel combination of an output capacitor and load for the charge transfer configuration. As before, operation of the converter involves alternating between the magnetizing and charge transferring configurations to transfer energy to the output capacitor and load under duty factor or variable frequency control using feedback of the output voltage to control timing of the switching.
The two inductor topologies can be extended to include three, four or any number of inductors. Additional inductors are connected in series during the magnetizing configuration and connected in parallel during the charge transfer configuration. Additional inductors require the use of additional switches to perform the series and parallel connections.
The remaining inductors are grounded during charge transfer.
The converters described above are ideally suited to powering one or more LEDs in a camera flash. In such applications, the current provided to the LED's may be efficiently controlled by placing current mirrors in series with the flash LEDs. The current mirrors may themselves be controlled through the use of a digital to analog converter responsive to an external signal.
As shown in
Topologically boost converter 70 includes MOSFETs 73 and 75 connected in series with inductors 74 and 76 and with voltage input Vbatt. Specifically N-channel MOSFET 73 is grounded with its drain connected to floating inductor 74 and the anode of rectifier 79 at node Vx. High-side inductor 76 is connected between Vbatt and node Vy. Node Vy is also connected to the anode of rectifier diode 78 and to the source or drain of MOSFET 75. The other drain or source terminal of MOSFET 75 is connected to floating inductor 74 at node Vw which is also connected to the drain of grounded N-channel MOSFET 77. MOSFET 75 may comprise a P-channel or N-channel MOSFET with appropriate changes in gate drive circuitry. In converter 70, the other terminal Vz of inductor 76 not connected to Vy is hardwired to the battery input so that Vz=Vbatt. The cathodes of rectifier diodes 78 and 79 are connected to the output node Vboost of the boost converter and the floating plate of filter capacitor 80. In the example shown, the electrical load of boost converter 70 comprises flash LED 81 and controlled current source 82.
Basic operation of the disclosed boost converter 70 involves alternating between magnetizing inductors 74 and 76, i.e. increasing the current flowing in the inductors by connecting them in series with the converter's battery input, and then transferring energy from the inductors into filter capacitor 80, i.e. charging the output capacitance to a voltage Vboost. PWM control circuit 72 determines the on time of MOSFETs 73 and 75 in response to feedback signal VFB. PWM control may comprise fixed frequency variable pulse width operation or variable frequency operation. In response to PWM control circuit 72, break-before-make BBM buffer 71 drives MOSFETs 73 and 75 to conduct in phase and for these MOSFETs to conduct out-of-phase with low-side N-channel MOSFET 77 thereby preventing overlapping or simultaneous conduction in all three MOSFETs.
Voltage input Vbatt to converter 70 may be a battery or any other voltage source, regulated or un-regulated. One common input is a single cell lithium ion battery whose voltage ranges from 4.2V fully charged down to 3V when discharged. New generation lithium ion batteries may, alternatively, operate down to 2V at full discharge. Typically LED voltages VLED, e.g. 4V to 5.5V, exceed Vbatt during camera flash operation and therefore require converter 70 to perform step-up voltage conversion, also known as boost conversion.
As shown in equivalent schematic 100 of
During magnetizing, the voltage Vx shown in graph 120 of
In the magnetizing condition since Vx<Vy<Vboost, rectifier diodes 78 and 79 are non-conducting and reversed biased by voltages Vr2 and Vr1 respectively. More specifically in this condition Vr1=Vboost−Vx≈Vboost and Vr2=Vboost−Vy<Vr1. Since the highest reverse bias occurs on rectifier 79, the rectifier diodes require a maximum blocking voltage sufficient to withstand the converter's output voltage Vboost. Either P-N diodes or Schottky diodes may be employed. During magnetization, MOSFET 77 is off so that node Vw exhibits a voltage 137 intermediate to Vx and Vy as shown in graph 136 of
Subsequent to magnetization, turning MOSFETs 73 and 75 off forces the voltage at nodes Vx and Vy to a positive potential above the boost converter's output voltage Vout. This voltage transient is a natural consequence of interrupting current in a conducting inductor as shown is equivalent schematic 105 of
With both diodes conducting, positive-going nodes Vx and Vy are essentially connected in parallel and the total inductor current IC delivered to capacitor 80 is the sum of the two inductor currents, namely IC=(IL1+IL2). If the average current of the triangle waveform of graph 131 is 1 A, then an average of 2 A will be delivered to the capacitor 80, twice the individual inductor current. To avoid this full current flowing through the battery the negative going sides of inductors 74 and 76 are not connected to a common node. Instead node Vw is grounded by conducting MOSFET 77 and is not connected to Vbatt. The voltage Vw during transfer has a voltage equal to the voltage drop across conducting MOSFET 77, i.e. where Vw=IL1·RDS(77) as shown by line 138 in graph 136.
The current path through floating inductor 74 during the transfer interval flows from ground through MOSFET 77, inductor 74, diode 79 and into capacitor 80 and does not flow from the battery. In contrast, the current path through high-side inductor 76 during the transfer interval flows from the battery Vbatt through inductor 76, diode 78 and into capacitor 80. In this manner only one of the two inductors, i.e. high-side inductor 76, results in battery current during energy transfer to capacitor 80.
During the transfer phase, forward-voltages Vf1 and Vf2, the voltage drops across rectifier diodes 79 and 78 respectively, have a magnitude from 0.3V to 0.7V if Schottky diodes are used to implement the rectifier diodes. If P-N diodes are used, the voltage drop will exceed 0.7V and a higher power loss will occur during every transfer interval. The voltage at Vx during charge transfer is therefore given by Vx=(Vboost+Vf1).
Similarly, the voltage at Vy during charge transfer is given by Vy=(Vboost+Vf2). Since IL1=IL2 the voltage drops Vf1 and Vf2 should be similar so that Vx≈Vy as shown by line 123 in graph 120.
When the high current load is not enabled the disclosed boost converter can alternate many cycles between equivalent-circuit 100 with current (1) during magnetizing and equivalent-circuit 105 with current (2) during transfer. This pre-flash operating condition is shown in graph 130 of
At time T2 flash LED 81 is enabled to conduct current ILED 132 as shown in graph 130. This condition is illustrated by equivalent-circuit 110 of
Returning to state diagram 140 of
Synchronous High Current Boost
Another embodiment of the disclosed high current capable dual inductor boost converter is illustrated in
The converter comprises similar components to converter 70 including PWM controller 151, BBM circuit 152, inductors 154 and 156, grounded N-channel MOSFETs 153 and 157, floating MOSFET 155, synchronous rectifier MOSFETs 158 and 160 with intrinsic P-N diodes 159 and 161 respectively, capacitor 162, LED 163 and controlled current source 164. During magnetizing MOSFETs 153 and 155 are both on and all the other power MOSFETs are all biased off. When MOSFETs 153 and 155 are biased off, the remaining MOSFETs 157 and synchronous rectifier MOSFETs 158 and 160 are turned on and conducting current.
Like floating MOSFET 155, synchronous rectifier MOSFETs 158 and 160 may comprise either N-channel or P-channel devices with appropriate changes in their gate drive circuitry. BBM circuitry 152 insures that MOSFETs 157, 158 and 159 remain off whenever MOSFETs 153 and 155 are on and vice versa, especially preventing simultaneous conduction during switching transitions. Specifically MOSFETs 158 and 160 are turned on for all or a portion of the time when diodes 159 and 160 are forward biased and carrying current. By shunting diode conduction with a conducting MOSFET channel the voltage drop is reduced from Vf to the smaller voltage drop given by IL·RDS and efficiency is improved.
If the application is for boost converter 150 is high current camera flash, the short flash duration means that synchronous rectification will not significantly improve average efficiency. The lower voltage drop across MOSFETs 158 and 160 does however divert inductor current from the rectifier diodes 159 and 161 and consequently ameliorates self heating in said diodes. It also improves the operating voltage range and the maximum load current since during charge transfer Vx=Vy≈Vboost
LED Flash Control
In example circuit 150 the LED flash current control is set by the current control device 164. In cases where the total LED current exceeds 1 A, it becomes advantageous to split the output into separate drives for two flash LEDs. This split output converter is illustrated in circuit 170 of
One example implementation of the split current sink high current LED driver is illustrated in circuit 180 of
During a flash condition, this reference bias across MOSFET 185 is connected to gates of MOSFETs 181 and 182 by pass transistor 183. In the case of shutting off the current sinks, MOSFET 183 is turned off while grounded MOSFET 184 pulls down on the gates of mirror MOSFETs 181 and 182.
Triple Series Inductor High Current Boost Converter
If even higher load currents are required, e.g. for very bright LED camera flash applications and xenon flash replacement, then a three-series-inductor version of the disclosed high current boost can be implemented as shown in
To complete the current path MOSFETs 210 and 209 are turned on during the transfer phase grounding the potential at nodes Vw and Vv. The Vz potential on inductor 208 is as shown hardwired to Vbatt. During charge transfer, only the current in inductor 208 flows through the battery Vbatt. The other inductors complete their conduction patch through ground. The boost capacitor 214 then may be used to drive flash LEDs 215 and 216 under the control of current sinks 217 and 218.
The condition of disclosed boost circuit 200 during magnetizing is illustrated in
During charge transfer or flash operation, the equivalent circuit is a quasi parallel circuit like that shown in
High Current Boost with No Battery Current During Charge Transfer
In
As illustrated in circuit 270 of
Throughout this document the term “ground” should be given the broadest possible interpretation. Thus, ground can refer to the specific case of zero volts but, where appropriate could also refer to a non-zero potential. This is specifically the case where an input supply has a positive and a negative pole. In such cases, the negative pole is electrically equivalent to ground.