Method for determining transparency in images extraction

Abstract

A method for determining transparency of images in extraction comprises various steps, including set transparent areas in Image 1 to black; set transparent areas in Image 2 to white; to perform an “exclusive or” operation on Image 1 and Image 2: subtract 1 from the resulting bitmap of the “exclusive or” operation, wherein the resulting bitmap after the “subtraction” operaton is called first mask bitmap; fill a first temporary bitmap with pixels all set to (254, 254, 254); perform an “exclusive or” operation on the first temporary bitmap and the bitmap for Image 1; fill a second temporary bitmap with pixels all set to (0, 0, 0); divide the resulting bitmap of the “exclusive or” operation on the first temporary bitmap and the bitmap for Image 1 by the second temporary bitmap, wherein the resulting bitmap after the “division” operation is called second mask bitmap; perform an “or” operation on the second mask bitmap and the original bitmap for Image 1; and perform an “or” operation on the first mask bitmap and the second mask bitmap. As a result, the pixels in the exporting image which have rgb values (254, 254, 254) are transparent; and the pixels in the exporting image, corresponding to the pixels in image 1 that had rgb values (254, 254, 254), now have rgb values (255, 255, 255).

Description

COPYRIGHT NOTICE

[0001] A portion of the disclosure of this patent document contains material that is subject to copyright protection. The copyright owner has no objection to the facsimile reproduction by anyone of the patent document or the patent disclosure, as it appears in the Patent and Trademark Office file or records, but otherwise reserves all copyright rights whatsoever.

BACKGROUND OF THE INVENTION

[0002] 1. Technical Field

[0003] The invention relates generally to image processing technology. More particularly, the invention relates to a process and method for algorithmic determination of image transparency.

[0004] 2. Description of Prior Art

[0005] When extracting images from another program, transparency needs to be handled correctly because the transparent portion of the images may change to another color during transformation.

[0006] One solution is to analyze each byte of the two input images directly in the visual basic code, but that is too slow. The alternative solution is to make use of the bitmap operations, which are faster, by setting the transparent portions of the images to white during the extraction process. This solution is still problematic because when making all white pixels transparent, any pixels that were white in the original image will be also changed to be transparent in the exported image.

[0007] What is desired is to develop a process for determining transparency of exported images wherein transparency is not shown where it should not be shown.

SUMMARY OF THE INVENTION

[0008] It has been determined that the transparent areas of images may be set to a different color. This leads to the idea that first set the transparent area of the image to white with rgb values (255, 255, 255) and extract the image, then set the transparent area to black with rgb values (0, 0, 0) and extract the image again, and finally compare the two resulting images such that the pixels that are different may be determined transparent.

[0009] The presently preferred embodiment of the invention determines transparency when an image is extracted, wherein all transparent pixels in the original image have rgb values (254, 254, 254) in the exported image, and any pixels with the rgb values (254, 254, 254) in the original image have rgb values (255, 255, 255) in the exported image. These numbers (254 and 255) are chosen because of their binary representations: 254 is 11111110 in binary and 255 is 11111111 in binary and because they are too similar for most users to be able to tell if one is changed to another.

[0010] The invention provides a mechanism that starts by creating a mask bitmap where all transparent areas have rgb values (254, 254, 254) and all other pixels have rgb values (0, 0, 0). Then the original bitmap is taken and all pixels that had rgb values (254, 254, 254) are changed to rgb values (255, 255, 255). Finally, the mask bitmap is applied to the resulting bitmap with an ‘or’ operation such that the set of pixels with rgb values (254, 254, 254) in the bitmap should be transparent. Because the pixels with rgb values (254, 254, 254) in the original bitmap has been changed to rgb values (255, 255, 255), these pixels are not changed to be transparent in the exported image.

BRIEF DESCRIPTION OF THE DRAWINGS

[0011] FIG. 1 is a flow diagram illustrating a process according to the invention, comprising various steps that collectively enable the functionality of the invention.

DETAILED DESCRIPTION OF THE INVENTION

[0012] FIG. 1 is a flow diagram illustrating a process according to the invention, comprising various steps that collectively enable the functionality of the invention. In the process, bitmap operations of ‘or’, ‘exclusive-or’, ‘divide’ and ‘subtract’ are used. These operations are common to most graphics systems and are efficient for bitmaps. In the examples shown by a set of tables given below, only nine pixels are included, and only single bytes are used to represent pixels to make the process easy to understand. In the real implementation, the number of pixels in an image is very large, and each pixel is represented by three bytes, one for each of red, green and blue.

[0013] The process according to the invention comprises the steps of:

[0014] Step 1: Create a First Mask Bitmap to Define the Transparent Areas

[0015] This step starts by combining two images (Image 1 and Image 2) with different background colors using an ‘exclusive or’ operation.

[0016] These two images have the same size and are the same except for transparent areas. Table 1 shows the key referring to positions of 9 pixels in the bitmap for the images. In image 1, all areas where should be transparent are set to black (0, 0, 0) as shown in Table 2. In image 2, all areas where should be transparent are set to white (255, 255, 255) as shown in Table 3.

TABLE 1
Key referring to positions in the bitmap
1, 1	2, 1	3, 1
1, 2	2, 2	3, 2
1, 3	2, 3	3, 3

[0017]

TABLE 2
Bitmap for Image 1 wherein transparent pixels are set to black (0, 0, 0)
0	0	0
128	255	0
128	128	254

[0018]

TABLE 3
Bitmap Image 2 wherein transparent pixels are set to white (255, 255, 255)
0	255	255
128	255	255
128	128	254

[0019] The ‘exclusive or’ operation on these two images creates two binary results for each position: it is 1 if two values in a same position are different, and it is 0 if two values in a same position are same.

[0020] Referring to Table 4, after the ‘exclusive or’ operation is performed, the resulting rgb values at positions (2,1), (3,1) and (3,2) are set to white (255, 255, 255) because the corresponding bits in each of these positions were different. All other areas are set to black (0, 0, 0) because the corresponding values in two images were equal.

TABLE 4
Bitmap after ‘exclusive or’ operation on Image 1 and Image 2
0	255	255
0	0	255
0	0	0

[0021] Then, subtract 1 from the bitmap shown in Table 4. After the ‘subtraction’ operation, all black pixels (0,0,0) remains unchanged, and all white pixels (255, 255, 255) are changed to quasi-white (254, 254, 254). These pixels with rgb values (254, 254, 254) at positions (2,1), (3, 1) and (3,2) are transparent areas. The bitmap shown in Table 5 is hereby named as the first mask bitmap.

TABLE 5
Bitmap after ‘subtraction’ (First Mask Bitmap)
0	254	254
0	0	254
0	0	0

[0022] Step 2: Change Pixels in the Original Bitmap that had RGB Values (254, 254, 254) to Pixels with RGB Values (255, 255, 255)

[0023] Two sub-steps are used to change any pixels that were originally quasi white (254, 254, 254) to white (255, 255, 255), so that transparency is not shown where it should not be shown. This is an operation on the original bitmap of Image 1, which had black pixels where the transparent areas should be shown. There may be other black pixels that can be handled by this algorithm.

[0024] Step 2A: Create a Second Mask Bitmap

[0025] This sub-step comprises:

[0026] 1. Filling a first temporary bitmap with pixels that are all set to quasi-white (254, 254, 254) as shown in Table 6.

TABLE 6
First temporary bitmap
254	254	254
254	254	254
254	254	254

[0027] 2. Combining the first temporary bitmap shown in Table 6 with the original bitmap for Image 1 shown in Table 2 using an ‘exclusive or’ operation. In the resulting bitmap shown in Table 7, the corresponding areas where they were quasi-white (254, 254, 254) in the original bitmap for image 1 shown in Table 2 now become black (0, 0, 0), and all other areas have random values (i.e. anything but 0, 0, 0).

TABLE 7
The resulting bitmap after ‘exclusive or’ operation
254	254	254
126	1	254
126	126	0

[0028] 3. Filling a second temporary bitmap with pixels that are all set to black pixels (0, 0, 0) as shown in Table 8.

TABLE 8
Second temporary bitmap
0	0	0
0	0	0
0	0	0

[0029] 4. Dividing the resulting bitmap shown in Table 7 by the second temporary bitmap shown in Table 8. After the ‘division’ operation, any black pixels (0, 0, 0) in the bitmap shown in Table 7 now become white (255, 255, 255) and any pixels that were anything else become black (0, 0, 0). The result of this operation shown in Table 9 is hereby named as the second mask bitmap.

TABLE 9
Mask bitmap after ‘division’ operation (Second Mask Bitmap)
0	0	0
0	0	0
0	0	255

[0030] Comparing Table 2 with Table 9, it is clear that any pixels that were originally quasi-white (254, 254, 254) in Image 1 (Table 2) are now white (255, 255, 255) in the mask bitmap (Table 9) and all other pixels in Image 1 (Table 2) are now black (0, 0, 0) in the mask bitmap (Table 9).

[0031] Step 2B: Apply the Second Mask Bitmap to the Original Bitmap

[0032] This is to apply the second mask bitmap (Table 9) from Step 2A to the original bitmap (Table 2) using an ‘or’ operation, wherein 0 or'd with anything returns the original value, and 255 (binary 11111111) or'd with anything returns 255.

[0033] After the ‘or’ operation, any pixels that were quasi-white (254, 254, 254) in Table 2 now become white (255, 255, 255) and all other pixels in Table 2 keep unchanged as shown in Table 10. In this operation, actually any pixels that had a byte with a value of 254 in Table 2 now is changed to a byte with a value of 255, which is almost indistinguishable in the exported image.

TABLE 10
Apply second mask bitmap to the original bitmap with an ‘or’ operation
0	0	0
128	255	0
128	128	255

[0034] Step 3: Apply First Mask Bitmap to Second Mask Bitmap

[0035] This is to apply the first mask bitmap from Step 1 shown in Table 5 to the second mask bitmap from Step 2B shown in Table 10 using an ‘or’ operation, wherein 0 or'd with anything returns the original value, and 255 (binary 11111111) or'd with anything returns 255.

[0036] The result of the ‘or’ operation is the bitmap where the set of pixels with rgb values (254, 254, 254) should be transparent. The transparent file is written out with that color marked as the transparent color. Any pixels that originally had rgb values (254, 254, 254) now have rgb values (255, 255, 255), a change that is very close to the original and not visible to most users.

[0037] Table 11 shows the expected result from applying the process to the two input bitmaps. The rgb values of the positions (1,2), (2,2), (1,3) and (2,3) in the exported image are unchanged from their original values. The position at (3,3) has changed from rgb values (254, 254, 254) to rgb values (255, 255, 255). This is desired because the image is to be saved for displaying all pixels with rgb values (254, 254, 254) as transparent and the pixel at the position (3,3) should not be transparent. The pixels at (2,1), (3,1) and (3,2) all have rgb values (254, 254, 254), which are treated as transparent.

TABLE 11
Apply the mask from Step 1 with an ‘or’ operation
0	254	254
128	255	254
128	128	255

[0038] Table 12 is the VBScript code implementation of the process described herein.

TABLE 12
VBScript
BEGIN
MultiUse = −1  ′True
END
Attribute VB_Name = “SXKeitherizer”
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = False
Attribute VB_Exposed = False
Option Explicit
Private Const TRANSPARENT_COLOR As Long = &HFEFEFE
Private Const BACKUP_COLOR As Long = &HFFFFFF
Private Const PIXEL_SCALE_MODE As Integer = 3
′ Takes two images which are the same size and the same except
for transparent
′ areas and changes the first image 11 so that those
transparent pixels are set to
′ rgb(254, 254, 254). If there were any pixels originally at
that value, they will
′ have been changed to rgb(255, 255, 255).
′
′ We assume that 11 has black pixels where there should be
′ transparency and that 12 has white pixels where there should
be transparency
Public Sub Keitherize(11 As LEAD, 12 As LEAD)
11.ScaleMode = PIXEL_SCALE_MODE
12.ScaleMode = PIXEL_SCALE_MODE
′ get the dimensions
Dim width As Single
Dim height As Single
width = 11.BitmapWidth
height = 11.BitmapHeight
′ create a mask where the transparent areas have pixels =
FEFEFE and all others areas
′ have pixels = 0
Dim transparentMask As LEAD
Set transparentMask = CreateTransparentMask(11, 12)
′ bump any pixels in 11 which are at transparentColor so
that they are at backupColor
Bump 11
′ set all pixels which are different in 11 and 12 equal to
transparentColor in 11
11.Combine 0, 0, width, height, transparentMask.Bitmap, 0,
0, CB_OP_OR
End Sub
′ changes 11 so that each pixel that was at rgb(254, 254, 254)
now becomes
′ rgb(255, 255, 255)
Private Sub Bump(11 As LEAD)
′ create a mask of the same size as 11 where each pixel
that was at
′ TRANSPARENT_COLOR is now BACKUP_COLOR and all
other pixels in the mask are 0
Dim mask As LEAD
Set mask = CreateMask(11, TRANSPARENT_COLOR)
′ apply the mask to 11, bumping pixels that had the
TRANSPARENT_COLOR value to the
′ BACKUP_COLOR. we are counting on the fact that
BACKUP_COLOR is all ones when we
′ do the or
11.Combine 0, 0, 11.Bitmapwidth, 11.BitmapHeight,
mask.Bitmap, 0, 0, CB_OP_OR
End Sub
′ creates a new image of the same size as 11 where all pixels
that were sourceColor in 11
′ are set to white and all other pixels are set to 0
Private Function CreateMask(11 As LEAD, sourceColor As Long)
As LEAD
Dim mask As New LEAD
mask.ScaleMode = PIXEL_SCALE_MODE
′ set the width and height of the mask to match the input
image
Dim width As Single
Dim height As Single
width = 11.Bitmapwidth
height = 11.BitmapHeight
mask.CreateBitmap width, height, 24
′ after this, the mask bitmap will have 0's where 11 had
sourceColor pixels and
′ random garbage everywhere else
mask.fill sourceColor
mask.Combine 0, 0, width, height, 11.Bitmap, 0, 0,
CB_OP_XOR
′ PENDING(greg) we could create a single black image which
we kept reusing
′ (growing as needed) if that sped things up
′ create a black image of the same size for use below
Dim tempBlackImage As New LEAD
tempBlackImage.ScaleMode = PIXEL_SCALE_MODE
tempBlackImage.CreateBitmap width, height, 24
tempBlackImage.fill RGB(0, 0, 0)
′ take all 0 pixels and make them into 255 pixels, and
convert the random garbage
′ into 0 pixels in a single step
mask.Combine 0, 0, width, height, tempBlackImage.Bitmap,
0, 0, CB_OP_DIVDST
Set CreateMask = mask
End Function
Private Function CreateTransparentMask(11 As LEAD, 12 As LEAD)
As LEAD
′ duplicate 11 and use it for the mask
Dim mask As New LEAD
maskScaleMode = PIXEL_SCALE_MODE
mask.Bitmap = 11.Bitmap
′ get the dimensions
Dim width As Single
Dim height As Single
width = 11.Bitmapwidth
height = 11.BitmapHeight
′ combine the two bitmaps so that pixels which were equal
(non-transparent)
′ are 0 and pixels which were unequal (transparent) are
white (0 xor 1 is 1)
mask.Combine 0, 0, width, height, 12.Bitmap, 0, 0,
CB_OP_XOR
′ subtract one from all the pixels, leaving 0 alone and
reducing the 255s to 254
Dim tempImage As New LEAD
tempImage.ScaleMode = PIXEL_SCALE_MODE
tempImage.CreateBatmap width, height, 24
tempImage-fill &H10101
mask.Combine 0, 0, width, height, tempImage.Bitmap, 0, 0,
CB_OP_SUBSRC
Set CreateTransparentMask = mask
End Function

[0039] In the process described herein, the value 254 is preferably used for the first mask bitmap i.e. the bitmap after ‘subtraction’ and the first temporary bitmap. In actuality, any eight-bit value close to white, such as 253 or 252, may be used. The problem is that, in the final step, the pixels of that value need to be displaced to the value of 255 and the further that value is from 255, the more noticeable the difference will be.

[0040] This invention is preferably used in a system where the input images does not encode transparency directly, but rather outputs transparent pixels in a color that is specified. In addition, the output images need to be set in a format e.g. GIF, PNG, which assigns transparency to pixels based on their color. Finally, this invention is optimized for situations where wholesale bitmap operations are faster than manipulating each byte individually. For instance, the MMX capability of recent Pentium chips (Intel Corporation, Santa Clara, Calif.) has this optimization.

[0041] Although the invention is described herein with reference to the preferred embodiment, one skilled in the art will readily appreciate that other applications may be substituted for those set forth herein without departing from the spirit and scope of the invention.

[0042] Accordingly, the invention should only be limited by the claims included below.

Claims

1. A method for determining transparency in images extraction, said method comprising the steps of: creating a first mask bitmap by combining a first image and a second image; wherein said first image and said second image have the same size and are the same except for transparent areas; creating a second mask bitmap which displaces pixels of first rgb values in said first image to second rgb values; applying said first mask bitmap to said second mask bitmap by performing an ‘or’ operation on said first mask bitmap and said second mask bitmap; wherein the pixels in the resulting bitmap of said ‘or’ operation which have said first rgb values are transparent; wherein the pixels in the resulting bitmap of said ‘or’ operation, corresponding to the pixels in said first image that had said first rgb values, have said second rgb values; and identifying the pixels in the resulting bitmap of said ‘or’ operation which have said first rgb values as transparent.

2. The method of claim 1, wherein said step of creating a first mask bitmap comprises the sub-steps of: setting transparent areas in said first image to black; and setting transparent areas in said second image to white.

3. The method of claim 2 and further comprising the sub-step of: performing an ‘exclusive or’ operation on said first image and said second image.

4. The method of claim 3 and further comprising the sub-step of: subtracting 1 from the resulting bitmap of said ‘exclusive or’ operation; wherein the resulting bitmap of said ‘subtraction’ operation is said first mask bitmap.

5. The method of claim 1, wherein said step of creating a second mask bitmap comprises the sub-steps of: filling a first temporary bitmap with pixels all set to rgb values (254, 254, 254); and performing an ‘exclusive or’ operation on said first temporary bitmap and said first image.

6. The method of claim 5 and further comprising the sub-steps of: filling a second temporary bitmap with pixels all set to rgb values (0, 0, 0); dividing the resulting bitmap of said ‘exclusive or’ operation on said first temporary bitmap and said first image by said second temporary bitmap; wherein the resulting bitmap of said ‘division’ operation is said second mask bitmap.

7. The method of claim 6 and further comprising the sub-step of: applying said second mask bitmap to said first image by performing an ‘or’ operation on said second mask bitmap and said first image; wherein the pixels with said first rgb values which first values are in said first image are changed to said second rgb values which second values are (255, 255, 255).

8. A process for determining transparency in images extraction, said process comprising the steps of: creating a first mask bitmap by combining a first image and a second image; wherein said first image and said second image have the same size and are the same except for transparent areas; creating a second mask bitmap which displaces pixels of rgb values (254, 254, 254) in said first image to rgb values (255, 255, 255); applying said first mask bitmap to said second mask bitmap by performing an ‘or’ operation on said first mask bitmap and said second mask bitmap; wherein the pixels in the resulting bitmap of said ‘or’ operation which have rgb values (254, 254, 254) are transparent; wherein the pixels in the resulting bitmap of said ‘or’ operation, corresponding to the pixels in said first image that had rgb values (254, 254, 254), have rgb values (255, 255, 255); and identifying the pixels in the resulting bitmap of said ‘or’ operation which have said first rgb values as transparent.

9. The process of claim 8, wherein said step of creating a first mask bitmap comprises the sub-steps of: setting transparent areas in said first image to black; and setting transparent areas in said second image to white.

10. The process of claim 9 and further comprising the sub-step of: performing an ‘exclusive or’ operation on said first image and said second image.

11. The process of claim 10 and further comprising the sub-step of: subtracting 1 from the resulting bitmap of said ‘exclusive or’ operation; wherein the resulting bitmap of said ‘subtraction’ operation is said first mask bitmap.

12. The process of claim 8, wherein said step of creating a second mask bitmap comprises the sub-steps of: filling a first temporary bitmap with pixels all set to rgb values (254, 254, 254); and performing an ‘exclusive or’ operation on said first temporary bitmap and said first image.

13. The process of claim 12 and further comprising the sub-steps of: filling a second temporary bitmap with pixels all set to rgb values (0, 0, 0); dividing the resulting bitmap of said ‘exclusive or’ operation on said first temporary bitmap and said first image by said second temporary bitmap; wherein the resulting bitmap of said ‘division’ operation is said second mask bitmap.

14. The process of claim 13 and further comprising the sub-step of: applying said second mask bitmap to said first image by performing an ‘or’ operation on said second mask bitmap and said first image; wherein the pixels with rgb values (254, 254, 254) in said first image is changed to rgb values (255, 255, 255).