Various embodiments relate to rotary oscillating bone, cartilage, and disk removal tool assemblies.
The prior art has provided rotary bone, cartilage, and disk removal tool assemblies. A problem with rotary bone, cartilage, and disk removal tool assemblies is caused by an encounter with fibrous material, which may wrap about a rotary cutting tool and cause unwanted damage. The prior art has also provided rotary oscillating bone, cartilage, and disk removal tool assemblies.
According to at least one embodiment, a bone, cartilage, and disk removal tool assembly is provided with a housing. A motor is mounted in the housing. A spindle is mounted for rotation to the housing. A rack-and-pinion mechanism is operably driven by the motor and connected to the spindle to oscillate the spindle for providing a rotary oscillating cutting operation.
According to at least another embodiment, a bone, cartilage, and disk removal tool assembly is provided with a housing. A motor is mounted in the housing. A plurality of cams is supported in the housing and driven for rotation by the motor. A plurality of followers is mounted for rotation to the housing, in engagement with the plurality of cams so that one rotation of the plurality of cams oscillates the plurality of followers more than once while preventing over-rotation of the plurality of followers. A spindle is mounted for rotation to the housing in engagement with the plurality of followers for providing a rotary oscillating cutting operation.
According to at least another embodiment, a bone, cartilage, and disk removal tool assembly is provided with a housing. A motor is mounted in the housing. A spindle is mounted for rotation to the housing. A mechanism is operably driven by the motor and connected to the spindle to oscillate the spindle for providing a rotary oscillating cutting operation. A peak angular acceleration of the spindle is less than nine million radians per second squared.
Other objectives and advantages of this invention will become apparent from the following description taken in conjunction with the accompanying drawings wherein are set forth, by way of illustration and example, certain embodiments of this invention. The drawings constitute a part of this specification and include exemplary embodiments of the present invention and illustrate various objects and features thereof.
As required, detailed embodiments of the present invention are disclosed herein; however, it is to be understood that the disclosed embodiments are merely exemplary of the invention that may be embodied in various and alternative forms. The figures are not necessarily to scale; some features may be exaggerated or minimized to show details of particular components. Therefore, specific structural and functional details disclosed herein are not to be interpreted as limiting, but merely as a representative basis for teaching one skilled in the art to variously employ the present invention.
With reference now to
The tool assembly 30 can be used in surgical operations, such as spinal surgery, wherein bone, cartilage, disk, and other non-fibrous body material may be removed, such as from the spine. The tool assembly 30 has an output spindle 36 which is driven to rotate in both directions, or rotary oscillate about its axis. The spindle 36 supports a cutting tool 38, which is driven by the spindle 36 to rotate partially in both directions with a limited range of rotation. Such oscillatory cutting is effective for bone, cartilage, and disk removal by a shearing operation, while effective in minimizing damage to any fibrous material. If the cutting tool 38 inadvertently contacts fibrous material, such as a nerve, during the cutting operation, the fibrous material is likely to be oscillated due to the flexibility of the fibrous material with minimal shearing, thereby minimizing damage to the fibrous material. Such rotary oscillating operations are common in cast removal tools.
The tool assembly 30 may receive power from an external supply, such as a direct current power supply cord 40. A power switch 42 may be provided on the housing for controlling the operation of the tool assembly 30. A light source 44 may also be provided on the housing for illuminating a work piece. The light source 44 may be a light emitting diode (LED).
A motor 52 is mounted in the housing 32 for providing a rotary input. The motor 52 is powered by the battery supply 46 when controlled by the electronics 48. The motor 52 drives a transmission 54 for converting continuous rotary motion from the motor 52 to rotary oscillation to the spindle 36. The spindle 36 is journalled in the housing 32 and driven by the transmission 54. The spindle 36 may be angled relative to the housing 32, as depicted, for ergonomics. Cooling fins, or a cooling fan, may be attached to or near the motor 52 for cooling the motor 52 and/or the tool assembly 30.
Referring now to
A guide 64 is supported in the housing 32 generally perpendicular to the motor axis 60. The guide 64 can be provided by a pair of pins 66. A shuttle 68 is provided on the guide 64 for reciprocating translation upon the guide 64. The shuttle 68 includes a channel 70 that is generally perpendicular to the guide 64. The channel 70 receives the roller 58 of the eccentric drive 56. The channel 70 cooperates as a follower for permitting the roller 58 to translate along a length of the channel 70 while driving the shuttle 68 along the guide 64. The guide 64 may utilize bearings and/or rollers to reduce friction.
The eccentric drive 56 and shuttle 58 cooperate as a Scotch-yoke mechanism for converting continuous rotary motion to linear reciprocating motion. The range of motion is illustrated in
Referring again to
Unlike prior art rotary oscillating bone, cartilage, and disk removal tool assemblies, the tool assembly 30 reduces vibrations to the user, and the tool assembly 30 is easier to grip during cutting operations. In order to obtain these product performance objectives, the motion of the cutting tool 38 avoids sudden or abrupt changes in direction or velocity. Instead, as the cutting tool 38 oscillates back and forth, its velocity smoothly transitions from zero to its peak value, then back to zero and repeats. The motion of the cutting tool 38 is controlled so that angular displacement, velocity and acceleration all follow harmonic signatures. That is to say, when plotted on a graph, these characteristics follow a sinusoidal-like curve. Of course, non-harmonic signatures may be employed.
The lateral displacement, velocity and acceleration of the shuttle 96 can be found at any point in time by the following equations.
Motor velocity: ω=2π(15000 rpm/60)=1570.8 radians/second);
wherein rpm is rotations per minute.
Motor Angle: θ=ωt;
wherein t is time.
Displacement: xshuttle=R sin(ωt);
wherein R is an offset of the roller 90 from the motor axis 60. For the depicted embodiment, R equals 3.75 millimeters (mm).
Shuttle Velocity: vshuttle=ωR cos(ωt).
Shuttle Acceleration: ashuttle=−ω2R sin(ωt).
The burr gear 74 is driven by the shuttle 68 via the gear rack 72. The burr gear 74 demonstrates similar motion, but instead of lateral displacement, it experiences angular displacement. The rotational motion of the burr gear 74 can be described by the following equations:
Angular Displacement: xburr=(R/Rburr)sin(ωt);
wherein Rburr is pitch radius of burr gear, which for the depicted embodiment is three millimeters.
Angular Velocity: vburr=ω(R/Rburr)cos(ωt).
Peak Angular Velocity: vburr(peak)=nωσ,
wherein σ is the oscillation amplitude, which is ½ of the total angular range (expressed in radians), and which for the depicted embodiment is also equal to Rburr; and n is the number of oscillations per motor revolution, which for the depicted embodiment is one.
Angular Acceleration: aburr=−ω2(R/Rburr)sin(ωt).
Peak Angular Acceleration: aburr(peak)=(nω)2σ.
Peak Angular Jerk: jburr(peak)=(nω)3σ.
Curve v shows that the peak angular velocity (VP=1,963 rad/sec=18,750 rpm) occurs at top dead and bottom dead center, exactly in the middle of the burr gear 74 swing. This is when the maximum amount of material is being removed from the material being cut. The shuttle 96 then allows the burr gear 74 to decelerate to a velocity of zero as it approaches maximum excursion, only to accelerate back through to maximum velocity on the return swing.
The motion of the burr gear 74 is smooth, with no sudden or abrupt changes in direction, velocity or acceleration. Although the motion of the depicted embodiment can be described with formulas in terms of sine and cosine, the design could be embodied in such a way that the motion of the burr gear 74 follows similarly looking harmonic curves that cannot be conveniently described with formulas in terms of sine and cosine.
Curve a illustrates that a peak angular acceleration of the spindle is less than five million radians per second squared at fifteen-thousand oscillations per minute. By analyzing the rate of change of acceleration, jerk can be determined as less than five billion radians per second cubed at fifteen-thousand oscillations per minute.
Although the motor speed is described as 15,000 rpm, the motor speed may be within a range of 5,000 rpm to 40,000 rpm according to one embodiment. The motor speed may be within a range of 15,000 rpm to 20,000 rpm according to another embodiment.
The transmission 84 in the tool assembly 30 causes the output torque at the burr gear 74 to vary from the input torque of the motor 86. This variance can be expressed as a Torque Ratio:
wherein Tburr is output torque applied to burr gear 74; and Tm is input torque supplied by the motor 86.
In other words, the transmission 84 causes the output torque to the burr gear 74 to be “XT times” the input torque from the motor 86 at any specified point in the displacement of the burr gear 74. This factor is a mechanical advantage of the transmission 84. The following analysis does not take into account inefficiencies (such as friction, air resistance and other losses) that will impede the transmission of torque from the motor 86 to the burr gear 74. However, steps have been taken to reduce such losses wherever possible, such as the use of bearings to reduce friction.
In general, Torque equals Force times Distance. The torque of the motor 86 acts on the eccentric drive 88, which then exerts a force on the shuttle 96 via the roller 90. The forces between the shuttle 96 and the roller 90 are equal and opposing, and in a direction perpendicular to the shuttle channel 98. The motor torque can therefore be expressed as this force multiplied by its perpendicular distance from the eccentric drive 88:
Tm=FpR cos(θ);
wherein Fp equals Fs, which are forces acting between the roller 90 and the shuttle 96.
When the shuttle 96 and the burr gear 74 approach a travel limit (as depicted in
As the roller 90 pushes on the shuttle 96, the shuttle 96 pushes on the burr gear 74 with the same amount of force. This force creates a torque on the burr gear 74 which can be expressed as:
Tburr=FburrRburr;
wherein Fburr equals Fs, which equals forces acting between the burr gear 74 and the shuttle 96. Rburr equals a pitch radius of the burr gear 74, which is three millimeters for the depicted embodiments. Combining the above equations, the torque on the burr gear 74 can be expressed as:
Therefore, the Torque Ratio can be expressed as:
This relationship between torque and velocity is well known. In general, the Torque Ratio is inversely proportional to the Velocity Ratio. For the embodiment of
vburr=ω(R/Rburr)cos(ωt) becomes vburr=ω(R/Rburr)cos(θ).
Then the Velocity Ration is:
which is the inverse of the Torque Ratio:
A dampening system may be provided in the tool assembly 30 to control vibration. The dampening system may include a dampening material or system between the motor 52 or transmission 54 and the housing 32 to minimize vibrations to the user. The dampening system or material can be provided externally or internally on the housing 32.
The electric motor 102 spins the cam mechanism 106 continually in one direction, which is clockwise in
In
The cam profiles 108, 110, 112, 114 cause the angular displacement, velocity and acceleration of the follower mechanism 116 to follow sinusoidal wave patterns. The motion can be described:
Angular Displacement: xburr=σ sin(nωt);
wherein n equals the number of full oscillations per motor revolution, which is two for the depicted embodiment. σ equals half of the full oscillation range (forty-five degrees or π/4 radian).
Angular Velocity: Vburr=nωσ cos(nωt).
Peak Angular Velocity: vburr(peak)=nωσ.
Angular Acceleration: aburr=−(nω)2σ sin(nωt).
Peak Angular Acceleration: aburr(peak)=(nω)2σ.
Peak Angular Jerk: jburr(peak)=(nω)3σ.
Curve a illustrates that a peak angular acceleration of the spindle is less than eight million radians per second squared at thirty-thousand oscillations per minute. By analyzing the rate of change of acceleration, jerk can be determined as less than twenty-five billion radians per second cubed at thirty-thousand oscillations per minute.
Since the cam mechanism 106 is attached directly to the motor 102, the torque on the cam mechanism 106 is equal to the torque of the motor 102. This torque can be expressed as a force acting at a perpendicular distance from the center of the cam mechanism 106. The following analysis does not take into account inefficiencies (such as friction, air resistance and other losses) that will impede the transmission of torque from the motor 102 to the spindle 126. However, steps have been taken to reduce such losses wherever possible, such as the use of bearings to reduce friction.
Tm=FcLc cos(Ac);
wherein Fc equals force of cam mechanism 106 acting on a cam follower 108, 110, 112, 114. Lc equals a length of cam contact point from center. Ac equals a push angle of cam profile, which is an angle normal from the contact point to the center.
In the case of the follower mechanism 116, the torque on the follower mechanism 116 is equal to the torque on the burr or cutting tool driven by the spindle 126, and can be expressed as:
Tburr=FfLf cos(Af);
wherein Ff equals a force of follower acting on cam; Lf equals a length of follower contact to center; and Af equals push angle of follower profile, which is an angle normal form the contact point to the center.
The maximum amount of torque that can be transmitted to the spindle 126 occurs during a steady state situation, such as if the spindle 126 becomes stuck. In such a situation, the forces acting between the cam mechanism 106 and the follower mechanism 116 are equal and opposing, and in a line perpendicular to a line that is tangent to the point of contact:
Fc=Ff
Combining the above equations, the torque on the spindle 126 or cutting tool burr can be expressed as:
Therefore, for this embodiment, the Torque Ratio can be expressed as:
When the follower mechanism 116 nears its end of travel, the velocity of the follower mechanism 116 is low compared to the velocity of the cam mechanism. Since the cam mechanism 106 has to move a relatively large angle in order to move the follower mechanism 116 a relatively small angle, it has a “mechanical advantage” with respect to torque. In other words, the cam mechanism 106 is able to transfer much more torque to the follower mechanism 116 just when it is needed most—when the follower mechanism 116 is moving its slowest and is the most likely to get stuck. As the formula suggests, the Torque Ratio increases as the length of “Lf cos(Af),” increases, and the length of “Lc cos(Ac)” decreases.
The Torque Ratio can also be computed by taking the inverse of the Velocity Ratio. The angular velocity of the spindle 126 or output burr can be rewritten in terms of θ (knowing that θ=ωt):
Vburr=nωσ cos(nωt) becomes Vburr=nωσ cos(nθ).
Then the Velocity Ratio is:
The Torque Ratio, being the inverse of the Velocity Ratio, becomes:
Because this formula for the Torque Ratio is different from the earlier formula, there are two formulas for computing the Torque Ratio. The first formula requires taking measurements of Lf, Lc, Af and Ac at the desired locations on the cam, since these values change all along the cam profiles. The second formula, however, can be calculated for all values of θ. Both methods are plotted in
The minimum torque applied to the spindle 126 equals 0.64 times (or sixty-four percent of) the motor torque. This minimum torque occurs at the midpoint of the spindle travel, when its velocity is greatest. The torque increases exponentially at the ends of the spindle travel, as the spindle velocity approaches zero. Oscillating twice per motor revolution causes the peak velocity to increase, but causes the minimum Torque Ratio to decrease, compared to oscillating only once per motor revolution at the same motor speed.
While various embodiments are described above, it is not intended that these embodiments describe all possible forms of the invention. Rather, the words used in the specification are words of description rather than limitation, and it is understood that various changes may be made without departing from the spirit and scope of the invention. Additionally, the features of various implementing embodiments may be combined to form further embodiments of the invention.
This application is a continuation application of U.S. patent application Ser. No. 16/266,802 filed on Feb. 4, 2019 (published as U.S. Pat. Pub. No. 2019-0209185), which is a divisional application of U.S. patent application Ser. No. 13/469,665 filed May 11, 2012, now U.S. Pat. No. 10,194,922, issued Feb. 5, 2019. The contents of the above referenced applications are incorporated herein by reference in their entirety for all purposes.
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3590661 | Chaveneaud | Jul 1971 | A |
6021538 | Kressner | Feb 2000 | A |
11389179 | Bono | Jul 2022 | B2 |
20070282344 | Yedlicka | Dec 2007 | A1 |
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Number | Date | Country |
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WO-9107116 | May 1991 | WO |
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20220313279 A1 | Oct 2022 | US |
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Parent | 13469665 | May 2012 | US |
Child | 16266802 | US |
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Parent | 16266802 | Feb 2019 | US |
Child | 17842296 | US |