Since moment of inertia has just mass (kg) of an area of radius R{circumflex over ( )}2 (meter squared), once it is in motion, it stays in motion. Initially, a massive flywheel at a standstill would require an equally massive force to rotate the mass requiring high inrush current for a motor to rotate. This is where a lever arm (moment arm) contributes a vital role of force amplification that substantially reduces input driving force. The first flywheel is driven by an external driving force at the center of mass M. At the rim of this first flywheel, a chain or a belt is connected to second flywheel at the rim for rim-to-rim connection. This maximizes transfer of moment of inertia between the two flywheels.
The second flywheel provides a wheel-and-axle driven by chain or belt offering ideal mechanical advantage (IMA)=R/r, where R is radius of this second flywheel, and r is radius of axle (drive shaft). This second flywheel, driven by IMA=R/r, drives the third flywheel at the center of mass for center-of-mass-to-center-of-mass or axle-to-axle (drive shaft-to-drive shaft) connection by transferring this amplified moment of inertia to the third flywheel. Short displacement at the axle (drive shaft) allows maximum transfer of amplified force to the third flywheel.
Third flywheel mass is increased to near, but not over, the magnitude of lever amplification ratio of R/r multiplied by the combined moment of inertia of two flywheels in series connected from rim-to-rim. This added mass does not increase load to the input driver because of the lever arm R/r provides the amplified force at the expense of moving short distance at the axle (drive shaft). Now, system has more mass added for more stored energy with minimally affecting the original input load. This is key to this invention. When two identical flywheels are in series and connected by a chain or a belt at rim, combined moment of inertia increases based on parallel axis theorem of point mass by M(R+R){circumflex over ( )}2, where R+R represents two flywheels in series.
By connecting a chain or a belt from rim of this third flywheel to an axle of a load can see the benefit of increased rotational kinetic energy coming from the mass increased. This is the first stage of sequential amplification of moment of inertia.
Itotal=½ M1*(R1){circumflex over ( )}2+(M1*(R1){circumflex over ( )}2)*2+½ M2*(R2){circumflex over ( )}2)+(M2*(R2){circumflex over ( )}2)*2= 5/2M1*(R1){circumflex over ( )}2+ 5/2M2*(R2){circumflex over ( )}2. Each of flywheel point mass MR{circumflex over ( )}2 is multiplied by 2 because there are two point mass present when we have two strand turning mechanism.
When mass and radius of first and second flywheels are same, M1=M2 and R1=R2, then, combined moment of inertia of these two flywheels is,
I
total=½MR{circumflex over ( )}2+M(R+R){circumflex over ( )}2+½MR{circumflex over ( )}2=5MR{circumflex over ( )}2.
This combined moment of inertia is further amplified by the R/r ratio. If R/r=10, M1 and M2=1, and R1 and R2=1, then the mass can be increased to 5MR{circumflex over ( )}2*(R/r)=50.
This means the third flywheel mass can be increased to 50 times of the first or second flywheel. If R=0.5, M=1, and R/r=10, then it becomes 5MR{circumflex over ( )}2*(R/r)=5*1*(0.5{circumflex over ( )}2)*10=12.5. As the flywheel gets smaller than 1 meter in radius, the effectiveness of R/r is reduced.
Third flywheel is connected to the fourth flywheel via a chain or a belt at the rim for rim-to-rim connection. This is the same configuration to the first two flywheels, and the output of the fourth flywheel is located at the center of mass that is the axis of rotation with IMA=R/r. Continuation of this serially configured connections is made for further increase in moment of inertia for greater rotational kinetic energy output.
Mass and radius of fourth flywheel is determined based on load requirements using the math equations shown above.
Next flywheel connected to fourth flywheel will have the same function as the third flywheel but with far more mass increase than the third flywheel. Output from this next flywheel will be second stage output of sequentially amplified moment of inertia applicable to driving a much heavier load than the first stage output.
When mass of flywheel is sequentially increased, this mass increase becomes the stored energy that is rotated at desired RPM for rotational kinetic energy that drives generators or other load while the input driving force is relatively unchanged except during the short period of inrush current at the startup.
Energy of a rotating round object is E=½*|*W{circumflex over ( )}2 where I is moment of inertia and W is angular velocity. So, moment of inertia and angular velocity are two components for energy. Therefore, increasing moment of inertia by increasing mass of subsequent flywheels is proportional to increasing rotational kinetic energy along with angular velocity.
Number | Date | Country | |
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63495457 | Apr 2023 | US |